如何通过特定的字符串元素将字符串列表拆分为字符串子列表 [英] How to split a list-of-strings into sublists-of-strings by a specific string element
本文介绍了如何通过特定的字符串元素将字符串列表拆分为字符串子列表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个单词列表如下.我想按.
拆分列表. Python 3中是否有任何更好或更有用的代码?
I have a word list like below. I want to split the list by .
. Is there any better or useful code in Python 3?
a = ['this', 'is', 'a', 'cat', '.', 'hello', '.', 'she', 'is', 'nice', '.']
result = []
tmp = []
for elm in a:
if elm is not '.':
tmp.append(elm)
else:
result.append(tmp)
tmp = []
print(result)
# result: [['this', 'is', 'a', 'cat'], ['hello'], ['she', 'is', 'nice']]
更新
添加测试用例以正确处理它.
Update
Add test cases to handle it correctly.
a = ['this', 'is', 'a', 'cat', '.', 'hello', '.', 'she', 'is', 'nice', '.']
b = ['this', 'is', 'a', 'cat', '.', 'hello', '.', 'she', 'is', 'nice', '.', 'yes']
c = ['.', 'this', 'is', 'a', 'cat', '.', 'hello', '.', 'she', 'is', 'nice', '.', 'yes']
def split_list(list_data, split_word='.'):
result = []
sub_data = []
for elm in list_data:
if elm is not split_word:
sub_data.append(elm)
else:
if len(sub_data) != 0:
result.append(sub_data)
sub_data = []
if len(sub_data) != 0:
result.append(sub_data)
return result
print(split_list(a)) # [['this', 'is', 'a', 'cat'], ['hello'], ['she', 'is', 'nice']]
print(split_list(b)) # [['this', 'is', 'a', 'cat'], ['hello'], ['she', 'is', 'nice'], ['yes']]
print(split_list(c)) # [['this', 'is', 'a', 'cat'], ['hello'], ['she', 'is', 'nice'], ['yes']]
推荐答案
使用itertools.groupby
from itertools import groupby
a = ['this', 'is', 'a', 'cat', '.', 'hello', '.', 'she', 'is', 'nice', '.']
result = [list(g) for k,g in groupby(a,lambda x:x=='.') if not k]
print (result)
#[['this', 'is', 'a', 'cat'], ['hello'], ['she', 'is', 'nice']]
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