如何将具有键值对的列表转换为字典 [英] How to convert a list with key value pairs to dictionary

问题描述

我想遍历此列表

['name: test1', 'email: [e-mail]', 'role: test', 'description: test', 'name: test2', 'email: [e-mail]', 'role: test2', 'description: test2', 'name: test3', 'email: [e-mail]', 'role: test3', 'description: test3']

，并返回每个组的词典列表.例如.

and return a list of dictionaries for each group. E.g.

[{name: 'test', email:'[e-mail]', role:'test', description:'test'}, {name: 'test2', email:'[e-mail]', role:'test2', description:'test2'}]

我尝试用，(逗号)分隔列表，并在其中搜索名称:".我可以返回一个字段，例如姓名，但正在努力链接到电子邮件，角色等.

I've tried splitting the list by , (comma) and searching it for 'name:'. I can return one field such as name, but am struggling to link to to the email, role, etc.

非常感谢您提前提供帮助.

Thanks for any help in advance.

推荐答案

无需事先知道每个字典具有的键数，就可以遍历列表，将每个字符串分成一个键和一个值，并按，如果密钥已经在最后一个字典中，则将新的dict添加到列表中，并继续通过该键将值添加到最后一个字典中:

Without having to know the number of keys each dict has in advance, you can iterate through the list, split each string into a key and a value by ': ', appending a new dict to the list if the key is already in the last dict, and keep adding the value to the last dict by the key:

output = []
for key_value in lst:
    key, value = key_value.split(': ', 1)
    if not output or key in output[-1]:
        output.append({})
    output[-1][key] = value

，以便给定存储在lst中的样本列表，output将变为:

so that given your sample list stored in lst, output would become:

[{'name': 'test1',
  'email': '[e-mail]',
  'role': 'test',
  'description': 'test'},
 {'name': 'test2',
  'email': '[e-mail]',
  'role': 'test2',
  'description': 'test2'},
 {'name': 'test3',
  'email': '[e-mail]',
  'role': 'test3',
  'description': 'test3'}]

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