Python-将列表列表划分为组 [英] Python - dividing a list-of-lists to groups

问题描述

请考虑以下简化情况:

lol = [['John','Polak',5,3,7,9],
       ['John','Polak',7,9,2,3],
       ['Mark','Eden' ,0,3,3,1],
       ['Mark','Eden' ,5,1,2,9]]

将基于前两个参数将此列表列表转换为列表列表的 pythonic和内存+速度高效方法是什么:

What would be a pythonic and memory+speed efficient way to transform this list-of-lists to a list-of-lists-of-lists based on the first two parameters:

lolol = [[['John','Polak',5,3,7,9],
          ['John','Polak',7,9,2,3]],
         [['Mark','Eden' ,0,3,3,1],
          ['Mark','Eden' ,5,1,2,9]]]

实际上-只要我具有正确的层次结构，任何其他数据结构也可以.例如，想到以下字典结构，但是创建它似乎效率不够高效，并且内存可能会比lolol解决方案要高.

Actually - any other data structure would also be ok, as long as I have the correct hierarchy. For example the following dictionary structure comes to mind, but creating it doesn't seem efficient speed-efficient enough, and the memory would probably be higher than the lolol solution.

dolol = {('John','Polak'):[[5,3,7,9],[7,9,2,3]],
         ('Mark','Eden') :[[0,3,3,1],[5,1,2,9]]}

推荐答案

用等效的Python 2补充delnan的答案:

To complement delnan's answer with a Python 2 equivalent:

from collections import defaultdict

dolol=defaultdict(list)
for data in lol:
    dolol[data[0],data[1]].append(data[2:])

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