如何将一个列表分成另一个列表指定的不同大小的卡盘? [英] How to split a list into chucks of different sizes specified by another list?

问题描述

我有一个数组，试图将其拆分成不同大小的块.

I have an array I am trying to split into chunks of different sizes.

在下面的示例中，loopN是卡盘尺寸.我尝试了各种方法来遍历loopN，但是无法弄清楚. list是我要拆分为大块的数组.

In the example below, loopN is are the chuck sizes. I have tried all sorts of ways to iterate through loopN, however can't figure it out. list is the array I am trying to split into chunks.

loopN = [2,3,1]
list = [1,2,3,4,5,6]

for i in range(0, len(list), loopN):
    chunks.append(list[i:i+loopN])

我想要的输出是[[1,2],[3,4,5],[6]].

如何将阵列分成大小不同的卡盘?

How do I split the array into chucks of different sizes?

推荐答案

，您需要遍历loopN列表，而不是list.然后，您可以获取列表的相应部分.

you need to loop over the loopN list, not list. Then you can get the appropriate slice of the list.

为了避免使用内置关键字，我在下面将list重命名为l.

I've renamed list to l below, to avoid using a built-in keyword.

i = 0
chunks = []
loopN = [2,3,1]
l = [1,2,3,4,5,6]

for chunksize in loopN:
    chunks.append(l[i:i+chunksize])
    i += chunksize

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