在Java中使用偏移量解析ISO-8601 DateTime [英] Parsing ISO-8601 DateTime with offset with colon in Java

问题描述

我在用Java解析日期时间时遇到麻烦，我使用了奇怪的日期时间格式. 如何在Java中解析2013-04-03T17:04:39.9430000+03:00日期时间以在Java中格式化dd.MM.yyyy HH:mm?

I have a trouble with parsing date time in java, I have a strange date time format. How can I parse 2013-04-03T17:04:39.9430000+03:00 date time in java to format dd.MM.yyyy HH:mm in java?

推荐答案

有问题的奇怪"格式为 ISO-8601 -用途非常广泛.您可以使用

The "strange" format in question is ISO-8601 - its very widely used. You can use SimpleDateFormat to reformat it in most way you please:

SimpleDateFormat inFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ");
DateTime dtIn = inFormat.parse(dateString});  //where dateString is a date in ISO-8601 format
SimpleDateFormat outFormat = new SimpleDateFormat("dd.MM.yyyy HH:mm");
String dtOut = outFormat.format(dtIn);
//parse it into a DateTime object if you need to interact with it as such

将为您提供您提到的格式.

will give you the format you mentioned.

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