如何在字符串中使用类名启动新的android活动? [英] How can I start a new android activity using class name in a string?

问题描述

我正在处理的android应用程序有问题.

I'm having a problem with an android application that I'm working on.

我的应用程序有几个部分，下一个加载的屏幕基于一个字符串.因此，第1部分的屏幕1将是S1S1.

My application has several sections and the next screen that loads is based on a string. So, screen 1 of section 1 would be, S1S1.

我的问题是，我如何才能基于字符串开始一项活动.我将S1S1保存在字符串中，让我们将其称为下一个活动.无需键入S1S1.class，我需要它来自字符串.我已经尝试了所有我能想到的东西，而Google并没有太大帮助.

My question is, how can I start an activity based on a string. I have S1S1 saved in a string, let us call it next activity. Rather than having to type S1S1.class, I need it to come from the string. I've tried everything I can think of and google hasn't helped much.

我尝试过的一些事情

Intent myIntent = new Intent(nextactivity);
Intent myIntent = new Intent(v.getContext(), getClass().getName().valueOf(nextactivity));
Intent myIntent = new Intent(v.getContext(), Class.forName(nextactivity));

并尝试与

startActivityForResult(myIntent, 0); 

，但似乎没有任何效果.有什么想法吗?

but nothing seems to work. Any ideas?

推荐答案

以下是您可以使用活动名称通过其开始活动的代码

Here is a code by which you can start activity using the name of the activity

String activityToStart = "com.example.MainActivity";
try {
    Class<?> c = Class.forName(activityToStart);
    Intent intent = new Intent(this, c);
    startActivity(intent);
} catch (ClassNotFoundException ignored) {
}

编辑

这里的类名将是带有包名的类的全名. 例如，如果包名称为x.y.z，并且活动名称为A，则活动A的全名将为x.y.z.A.

Here class name will be full name of the class with the package name. For example if your package name will be x.y.z and if you have Activity name called A then the full name of the Activity A will be x.y.z.A.

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