如何从Java控制台应用程序中的扫描程序读取字符串? [英] How to read strings from a Scanner in a Java console application?

问题描述

import java.util.Scanner;
class MyClass
{
    public static void main(String args[])
    {
        Scanner scanner = new Scanner(System.in);
        int employeeId, supervisorId;
        String name;
        System.out.println("Enter employee ID:");
        employeeId = scanner.nextInt();
        System.out.println("Enter employee name:");
        name = scanner.next();
        System.out.println("Enter supervisor ID:");
        supervisorId = scanner.nextInt();
    }
}

我在尝试输入名字和姓氏时遇到了此异常.

I got this exception while trying to enter a first name and last name.

Enter employee ID:
101
Enter employee name:
firstname lastname
Enter supervisor ID:
Exception in thread "main" java.util.InputMismatchException
    at java.util.Scanner.throwFor(Unknown Source)
    at java.util.Scanner.next(Unknown Source)
    at java.util.Scanner.nextInt(Unknown Source)
    at java.util.Scanner.nextInt(Unknown Source)
    at com.controller.Menu.<init>(Menu.java:61)
    at com.tests.Employeetest.main(Employeetest.java:17)

但是如果我只输入名字，它会起作用.

but its working on if I only enter the first name.

Enter employee ID:
105
Enter employee name:
name
Enter supervisor ID:
501

我想要的是读取完整的字符串，无论它是以name还是firstname lastname的形式给出的.这是什么问题?

What I want is to read the full string whether it is given as name or as firstname lastname. What's the problem here?

推荐答案

Scanner scanner = new Scanner(System.in);
int employeeId, supervisorId;
String name;
System.out.println("Enter employee ID:");
employeeId = scanner.nextInt();
scanner.nextLine(); //This is needed to pick up the new line
System.out.println("Enter employee name:");
name = scanner.nextLine();
System.out.println("Enter supervisor ID:");
supervisorId = scanner.nextInt();

呼叫nextInt()是一个问题，因为它没有接听新行(当您按下Enter键时).因此，在此之后调用scanner.nextLine()即可完成工作.

Calling nextInt() was a problem as it didn't pick up the new line (when you hit enter). So, calling scanner.nextLine() after that does the work.

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