Powershell:使用过程对象捕获标准输出和错误 [英] Powershell: Capturing standard out and error with Process object

问题描述

我想从PowerShell启动Java程序并将结果打印在控制台上.

I want to start a Java program from PowerShell and get the results printed on the console.

我已遵循此问题的说明: 通过启动过程捕获标准输出和错误

I have followed the instructions of this question: Capturing standard out and error with Start-Process

但是对我来说，这不符合我的预期.我在做什么错了?

But for me, this is not working as I expected. What I'm doing wrong?

这是脚本:

$psi = New-object System.Diagnostics.ProcessStartInfo
$psi.CreateNoWindow = $true
$psi.UseShellExecute = $false
$psi.RedirectStandardOutput = $true
$psi.RedirectStandardError = $true
$psi.FileName = 'java.exe'
$psi.Arguments = @("-jar","tools\compiler.jar","--compilation_level",   "ADVANCED_OPTIMIZATIONS", "--js", $BuildFile, "--js_output_file", $BuildMinFile)
$process = New-Object System.Diagnostics.Process
$process.StartInfo = $psi
$process.Start() | Out-Null
$process.WaitForExit()
$output = $process.StandardOutput.ReadToEnd()
$output

$output变量始终为空(当然，控制台上不会打印任何内容).

The $output variable is always empty (and nothing is printed on the console of course).

推荐答案

RedirectStandardError属性上的文档表明，最好将WaitForExit()调用放在ReadToEnd()调用之后.以下内容对我来说是正确的:

The docs on the RedirectStandardError property suggests that it is better to put the WaitForExit() call after the ReadToEnd() call. The following works correctly for me:

$psi = New-object System.Diagnostics.ProcessStartInfo 
$psi.CreateNoWindow = $true 
$psi.UseShellExecute = $false 
$psi.RedirectStandardOutput = $true 
$psi.RedirectStandardError = $true 
$psi.FileName = 'ipconfig.exe' 
$psi.Arguments = @("/a") 
$process = New-Object System.Diagnostics.Process 
$process.StartInfo = $psi 
[void]$process.Start()
$output = $process.StandardOutput.ReadToEnd() 
$process.WaitForExit() 
$output

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