将jquery变量合并到一个选择器中? [英] Combine jquery variables into one selector?

问题描述

我正在寻找一种组合jquery变量的方法.通过相关问题，似乎没有人在尝试我想做的事.

I'm looking for a way to combine jquery variables. Looking through related questions, nobody seems to be trying what I want to do.

$("body, div, p")是通过选择器组合的一种方法，但是在将选择器分配给变量之后，如何以类似的方式组合它们?

$("body, div, p") is one method of combining by selectors, but after you assign a selector to a variable, how do you combine them in a similar fashion?

这是我尝试过的一种方法，但是没有使它起作用.我还尝试将它们放入数组中(只需在$ body之前和$ p之后添加方括号).

Here is one method I tried, but did not get it to work. I also tried putting them into an array (by simply adding brackets before $body and after $p).

$body = $("body");
$div = $("div");
$p = $("p");
$mixed = $($body, $div, $p);
// $mixed = $("body, div, p"); is NOT what I am looking for

在我的实际脚本中，我已经为变量分配了一些<select>输入.我想将它们分组，所以说我有一个<select>带有"FRUIT"，另一个有"VEGETABLES"，我可以将它们都放入一个名为"PRODUCE"的jquery变量中.然后，如果我需要对两者都执行任何操作，则可以使用Produce代替.

In my actual script I've got some <select> inputs assigned to variables. I would like to put them into groups, so say I have a <select> which has "FRUIT" and another one that has "VEGETABLES", I could put them both into a jquery variable called "PRODUCE". Then if I need to perform anything on both of the two, I use produce instead.

...不过，这可能只是做事的愚蠢方式.

...This might just be a stupid way to do things, though.

推荐答案

也许您正在寻找 .add( )?

$mixed = $body.add($div).add($p);

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