用jquery/ajax更新django表单 [英] update a django form with jquery/ajax

问题描述

我想在下拉列表的change事件上更新表单.

I want to update a form on the change event of my drop down list.

这是我的观点:

from django.utils import simplejson
response_dic={}
#drop down list
actToValidateId=add_form.cleaned_data['actsToValidate'].pk
act=ActsIdsModel.objects.get(id=actToValidateId)
ids_form = ActsIdsForm(instance=act)

ids_form_dic={}
for field in ids_form.fields:
    ids_form_dic[field]=getattr(act, field)
response_dic['ids_form']=ids_form_dic
response_dic['act']=dict([(attr, getattr(act, attr)) for attr in [f.name for f in act._meta.fields]])

return HttpResponse(simplejson.dumps(response_dic), mimetype="application/json")

这是JavaScript代码:

Here is the javascript code:

function display_act_ids(choice)
{
    $form=$('#act_ids_form');
    var form_data = $form.serialize();
    $.ajax
    ({
        url: $form.attr('action'),
        type: 'POST',
        dataType: 'json',
        data: form_data,
        success: function(result)
        {
            alert(result.ids_form.fileNoCelex);
        }
    });

    //don't submit the form
    return false;
}

现在，有两个问题:

1/如果我想为表单控件分配相应的值，则可以如下更新成功函数:

1/ If i want to assign the corresponding values to my form controls, I can update the success function as below:

$("#myfield").val(result.ids_form.myfield);

但是，如果我要填写很多字段怎么办?有自动执行此功能的功能吗?也许循环就可以了...

But what if I have many fields to fill? Is there a function to do that automatically? Maybe a loop would do...

2/我的主要问题:我在模板的很多地方(而不是在表单中)使用我的act实例(和其他变量).例如:

2/My main problem: I use my act instance (and other variables) in lots of places in my template (not in my form). For example:

{% if act.councilPath %}
    <div class="row-fluid">{{ act.councilPath }}</div>
{% endif %}

以这种方式，不可能使用ajax.这意味着我必须重写我的模板才能正常工作.例如:

In such a way, it is impossible to use ajax. Which means I have to rewrite my template to have it work. For example:

<div id="council_path" class="row-fluid"></div>

在我的成功函数中:

 $("#council_path").html(result.act.councilPath);

这将是很长的更新.有没有更好的方法，例如ajax发布并加载"?

This would be very long to update. Is there a better way to do, such as an ajax "post and load"?

请告诉我我是否不清楚.

Please tell me if I am not clear.

推荐答案

要使用jQuery/ajax更新django表单，这是我的方法... 三个关键点:将表单模板放在单独的html页面中，在视图中使用render_to_string并将html响应发送到ajax.

To update a django form with jquery/ajax, here is my method... Three key points: put your form template in a separate html page, use render_to_string in your view and send an html response to ajax.

index.html页面:

{% extends "base.html" %}

{% block content %}
    <!-- you can put here everything that doesn't need to be updated (text, css inclusion, etc.) -->
    <!-- act validation form -->
    <form id="act_ids_form"  class="form-inline" action="{% url act_ids %}" method="post">{% csrf_token %}
            <!-- drop down list -->
            <div id="actsToValidateChoice" class="fieldWrapper">
                  {{ add_form.actsToValidate.errors }}
                  {{ add_form.actsToValidate }}
            </div>
            <!-- div to update the part of the form that must be updated -->
            <div id="act_ids_form_div">{% include form_template %}</div>
    </form>

{% endblock %}

forms.py:

class ActsAddForm(forms.Form):
        #drop down list      
        actsToValidate=forms.ModelChoiceField(queryset=ActsIdsModel.objects.filter(validated=0), empty_label="Select an act to validate", widget=forms.Select(attrs={'onchange': 'display_act_ids()'}))

form.html:

<!-- act ids form -->
<!-- put here everything that must be updated on the change of your drop down list -->
<div class="row-fluid">{{ ids_form.non_field_errors }}</div>

{% if act.councilPath %}
        <div class="row-fluid"><a class="info_msg" href="{{act.councilPath}}" target="_blank">{{ displayName.councilPath }}</a></div>
{% endif %}

<table class="table table-bordered table-hover table-condensed span12">
        <tr>
            {% for field in ids_form %}
                <td>
                    <div class="fieldWrapper">
                        {{ field.errors }}
                        {{ field }}
                    </div>
                </td>
            {% endfor %}
        </tr>
</table>

urls.py:

from django.conf.urls import patterns, url

urlpatterns = patterns('actsIdsValidation.views',
    url(r'^/?$', 'act_ids', name='act_ids'),
    url(r'^form.html$', 'act_ids', name='act_ids'),
)

views.py:

def act_ids(request):
    response_dic={}
    #html page of the form
    form_template='actsIdsValidation/form.html'

    if request.method == 'POST':
        #if drop down list not empty
        if request.POST["actsToValidate"]!="":
            #add form: contains the drop down list only
            add_form = ActsAddForm(request.POST);
            actToValidateId=request.POST["actsToValidate"].pk
            act=ActsIdsModel.objects.get(id=actToValidateId)
            ids_form = ActsIdsForm(instance=act)
            response_dic['ids_form']=ids_form
            response_dic['act']=act

            return HttpResponse(render_to_string(form_template, response_dic, RequestContext(request)))

    #GET
    #unbound ids_form
    response_dic['ids_form'] = ActsIdsForm()
    response_dic['add_form'] = ActsAddForm()
    response_dic['form_template'] = form_template
    return render_to_response('actsIdsValidation/index.html', response_dic, context_instance=RequestContext(request))

Ajax调用:

function display_act_ids()
{
    $form=$('#act_ids_form');
    var datastring = $form.serialize();
    $.ajax({
        type: "POST",
        url: $form.attr('action'),
        dataType: 'html',
        data: datastring,
        success: function(result)
        {
            /* The div contains now the updated form */
            $('#act_ids_form_div').html(result);
        }
    });

    //don't submit the form
    return false;
}

Voila！

这篇关于用jquery/ajax更新django表单的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！