在jQTouch中确定上一页(即引荐来源网址) [英] Detemine the previous page (i.e. referrer) in jQTouch

问题描述

我正在尝试确定上一页(例如引荐来源网址)，以便决定是否显示后退"按钮.

I am trying to determine the previous page (e.g. the referrer) in order to decide whether to display the back button.

我试图检查$('.current').data('referrer')，但并非始终设置该值.实际上，它通常没有设置.似乎也没有设置history.previous和document.referrer.

I tried to check for $('.current').data('referrer'), but it is not always set. In fact, it is often not set. history.previous and document.referrer do not seem to be set, either.

有人可以启发我吗?

推荐答案

我不想走这条路，但我能找到的唯一可行的解​​决方案是jQTouch保留内部变量(即hist).浏览记录.因此，我对jqouth.js进行了以下更改(修订146):

I didn't want to go down this path, but the only viable solution I can find is the internal variable (i.e. hist) that jQTouch keeps the browsing history. So, I made the following changes to jqouth.js (revision 146):

在第256行附近，在私有功能"部分之前，插入:

around line 256, just before the private functions section, insert:

function getHistory() { return hist; }

在625行附近，在submitForm: submitForm之前，插入:

around line 625, just before submitForm: submitForm, insert:

getHistory: getHistory,

然后我可以使用以下内容查看浏览历史记录:

Then I can look at the browsing history with something like:

var previousPageID = jQT.getHistory()[1].id;

一个警告是，应注意不要意外操纵历史对象.

One caveat is, care should be taken not to accidentally maniplulate the history object.

编辑:

自版本14开始，作者就公开了内部历史记录对象. 2010年10月，因此可以直接访问它，即jQT.hist.

The author has exposed the internal history object since the version on 14 October 2010, so it can be directly accessed, i.e. jQT.hist.

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