jQuery IF具有多个值的show和hide元素 [英] JQuery IF with multiple value show and hide element
本文介绍了jQuery IF具有多个值的show和hide元素的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我对jquery还是很陌生,请为我的以下问题提供任何帮助:
I'm quite new with jquery, kindly need any of your assitance for my below question:
我有一个输入,用户可以输入小于3位数字的 数字 ,并以 前缀以某些"数字开头 ,如果满足条件,则会显示特定的元素,否则将被隐藏.
I have an input where users can type some number that less than 3 digit, and have prefix start with "certain" number, if condition is met, a specific element will be displayed, otherwise it will be hidden.
我的问题是,如果我有10个或更多的这种情况,我的代码将会很长,并且明显会降低性能. 有没有简单的方法可以做到这一点?
My problem is, if I have 10 or more of this condition, my code will be so long, and obviously decrease the performance. Is there any simple way to achieve this ?
$(function(c) {
$('#check').on('keyup change', function(c) {
var one = $('#check');
if( (one.val() == 123) || (one.val() == 124) ) {
$('#one').show();
} else if (this.value.length < 3 ) {
$('#one').hide();
}
});
$('#check').on('keyup change', function(c) {
var two = $('#check');
if( (two.val() == 234) || (two.val() == 235) ) {
$('#two').show();
} else if (this.value.length < 3 ) {
$('#two').hide();
}
});
$('#check').on('keyup change', function(c) {
var three = $('#check');
if( (three.val() == 345) || (three.val() == 346) ) {
$('#three').show();
} else if (this.value.length < 3 ) {
$('#three').hide();
}
});
});
#one {
display: none;
}
#two {
display: none;
}
#three {
display: none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.0/jquery.min.js"></script>
<input type="text" id="check" maxlength="10">
<div id="one">
<br>
ONE
</div>
<div id="two">
<br>
TWO
</div>
<div id="three">
<br>
THREE
</div>
提前谢谢!
推荐答案
尝试一下:
$('#check').on('keyup change', function(c) {
//initially hide all
if(this.value.length < 3){
$('#three, #two, #one').hide();
}
else{
switch(parseInt(this.value)){
case 123: case 124: $('#one').show(); break;
case 234: case 235: $('#two').show(); break;
case 345: case 346: $('#three').show(); break;
}
}
});
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