可排序的jQuery UI:如何从已连接列表中排除项目? [英] jQuery UI sortable: How to exclude items from connected lists?

问题描述

我有两个连接的列表(左/右列)，因此我可以将项目从一列(左)拖放到另一列(右).

I have two lists (left/right coloumn) which are connected, so I can drag&drop items from one column (left) to the other (right).

如何在不能将其拖放到源列表中的功能的同时从列表1(左)中排除不应拖动到列表2(右)的特定项目?

How can I exclude specific items from list1 (left) that should NOT be draggable to list2 (right) while keeping the functionality to drag&drop them inside their source-list?

提琴: http://goo.gl/7ZKfrl

推荐答案

我使用了以下内容，并且对我有用.有相同的要求.

I used the following and it worked for me. Had same requirement.

$("ul#YourLeftListID li").each(function () {
            if ($(this).text() == 'None') {
                $(this).draggable({ disabled: true })
            }
        });

希望这会有所帮助.

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