javascript根据关联数组键值从数组中查找值 [英] javascript find value from array based on associative array key value

问题描述

我有一个关联数组:

var array1 = {
    a1: {
        id: "box1",
        title: "box 1"
    },
    a2: {
        id: "box2",
        title: "box 2"
    },
    a3: {
        id: "box3",
        title: "box 3"
    }
};

然后我有了另一个引用第一个数组的数组:

I then have another array which has references to the first array:

var array_order = ["a3:positionA", "a2:postitionB", "a1:positionC"];

我想遍历第一个列表，然后使用第二个列表查找位置文本

I want to loop through the first list and then use the second list to find the position text

我正在使用jQuery，所以我有

I am using jQuery so I have

$.each(array1, function(i,o) {
  something in here where I can use i to find out what position. e.g. if a1 I would get positionC
}

推荐答案

在array_order而不是array1上更轻松，更快地进行迭代:

Easier and faster iterate over array_order instead of array1:

for( var i = 0, len = array_order.length; i < len; i++ ) {
    var ref = array_order[i].split(':');

    if( ref.length === 2 && ({}).hasOwnProperty.call( array1, ref[0] ) ) {
        var array1Property = array1[ ref[0] ];
        var array1PropertyPosition = ref[1];
    }
} 

也可以实现对array1属性的迭代，但这要慢得多:

Iteration over array1 properties can be realized also, but it's significantly slower:

for( var prop in array1 )
    if( ({}).hasOwnProperty.call( array1, prop ) )
        for( var i = 0, len = array_order.length; i < len; i++ ) {
            var ref = array_order[i].split(':');
            if( ref.length === 2 && prop === ref[1] ) {
                var array1Property = array1[ prop ];
                var array1PropertyPosition = ref[1];
            }
        }

而且jQuery中也不需要.

And there is no need in jQuery.

这篇关于javascript根据关联数组键值从数组中查找值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！