QUnit/Sinon:测试一个功能,该功能检查是否启用了cookie [英] QUnit/Sinon: testing a function which checks if cookies are enabled
问题描述
我有以下(简体)javascript模块,该模块使用jQuery Cookie插件来检查是否启用了cookie.如果Cookie被禁用,则会警告用户:
I have the following (simplified) javascript module which uses jQuery Cookie plugin to check if cookies are enabled. If cookies are disabled it warns the user:
var cookiePolicy = (function () {
var cookiesEnabled = function () {
return $.cookie('check', 'valid', { expires: 1 }) && $.cookie('check') == 'valid';
};
return {
updateCookiePolicy: function () {
if (!cookiesEnabled()) {
$("#cookie-policy").append('<p id="cookie-warning">Cookies are disabled. Some features of this site may not work correctly.</p>');
}
}
};
})();
我有以下单元测试:
QUnit.test("When cookies are enabled the cookie policy text remains unchanged", function (assert) {
sinon.mock($).expects("cookie").once().withExactArgs("check", "valid", { expires: 1 });
sinon.mock($).expects("cookie").once().withExactArgs("check").returns("valid");
cookiePolicy.updateCookiePolicy();
assert.equal(0, $('#cookie-warning').length, "Failed!");
});
测试失败,因为"cookie已被包装".我认为这是因为我在嘲笑$ .cookie的设置和读取.在该测试中,如何设置和读取对$ .cookie的调用?
The test fails because "cookie is already wrapped". I assume this is because I am mocking $.cookie for both set and read. How can I mock the call to $.cookie for both setting and reading in this test?
推荐答案
您的假设是正确的.根据您使用的Sinon版本,您可以执行以下操作:
Your assumption is correct. Depending on the version of Sinon you're using, you could do something like this:
// UUT
var foo = {
bar: function() {}
};
// Test setup
var mock = sinon.mock(foo);
var expectation = mock.expects('bar').twice();
expectation.onFirstCall().stub.calledWithExactly('baz');
expectation.onSecondCall().stub.calledWithExactly('qux');
// Test
foo.bar('baz');
foo.bar('qux');
mock.verify();
顺便说一句,在不使用.verify()
的情况下使用Sinon模拟是很奇怪的.也许存根会更合适?
BTW, it's strange to use Sinon mocks without using .verify()
. Maybe stubs would be a better fit?
这篇关于QUnit/Sinon:测试一个功能,该功能检查是否启用了cookie的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!