GCC问题:使用依赖于模板参数的基类成员 [英] GCC issue: using a member of a base class that depends on a template argument

问题描述

以下代码无法使用gcc进行编译，但可以使用Visual Studio进行编译:

The following code doesn't compile with gcc, but does with Visual Studio:

template <typename T> class A {
public:
    T foo;
};

template <typename T> class B: public A <T> {
public:
    void bar() { cout << foo << endl; }
};

我得到了错误:

test.cpp:在成员函数"void B :: bar()"中:

test.cpp: In member function ‘void B::bar()’:

test.cpp:11:错误:在此范围内未声明"foo"

test.cpp:11: error: ‘foo’ was not declared in this scope

但是应该！如果我将bar更改为

But it should be! If I change bar to

void bar() { cout << this->foo << endl; }

然后进行 编译，但是我认为我不必这样做. GCC遵循的C ++正式规范中是否有某些内容，还是只是一个古怪的东西?

then it does compile, but I don't think I have to do this. Is there something in the official specs of C++ that GCC is following here, or is it just a quirk?

推荐答案

此问题在 gcc-3.4 . C ++解析器在该版本中的要求更加严格-按照规范，但是对于具有旧版或多平台代码库的人来说仍然有些烦人.

This changed in gcc-3.4. The C++ parser got much more strict in that release -- per the spec but still kinda annoying for people with legacy or multi-platform code bases.

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