通过Python中元组的第一个元素自然地对字母数字元组列表进行排序 [英] Naturally sort a list of alpha-numeric tuples by the tuple's first element in Python

问题描述

一个先前的stackoverflow问题解释了如何对一个字母数字字符串列表.我想按元组的第一个元素按字母顺序对元组列表进行排序.

A previous stackoverflow question explains how to sort a list of strings alpha-numerically. I would like to sort a list of tuples alphanumerically by the tuple's first element.

示例1:

>>> sort_naturally_tuple([('b', 0), ('0', 1), ('a', 2)])
[('0', 1), ('a', 2), ('b', 0)]

示例2:

>>> sort_naturally_tuple([('b10', 0), ('0', 1), ('b9', 2)])
[('0', 1), ('b9', 2), ('b10', 0)]

更新:要强调字母数字因子，请查看示例2.

Update: To emphasize the alphanumeric factor, please review example 2.

推荐答案

使用另一个问题的第二个答案，一般来说，它支持基于项目的任何方法作为获取密钥的基础:

Using the second answer from the other question, generalized to support any method on item as the basis for getting the key:

import re
from operator import itemgetter

def sorted_nicely(l, key):
    """ Sort the given iterable in the way that humans expect."""
    convert = lambda text: int(text) if text.isdigit() else text
    alphanum_key = lambda item: [ convert(c) for c in re.split('([0-9]+)', key(item)) ]
    return sorted(l, key = alphanum_key)


print sorted_nicely([('b10', 0), ('0', 1), ('b9', 2)], itemgetter(0))

此答案与该答案完全相同，只是泛化为使用任何可调用对象作为对项目的操作.如果只想对字符串执行操作，则可以使用lambda item: item；如果要对列表，元组，字典或集合进行操作，则可以使用operator.itemgetter(key_or_index_you_want)；或者，如果要对字符串进行操作，则可以使用operator.itemgetter(key_or_index_you_want)它可以在类实例上使用operator.attrgetter('attribute_name_you_want').

This is exactly the same as that answer except generalized to use any callable as the operation on item. If you just wanted to do it on a string, you'd use lambda item: item, if you wanted to do it on a list, tuple, dict, or set, you'd use operator.itemgetter(key_or_index_you_want), or if you wanted to do it on a class instance you could use operator.attrgetter('attribute_name_you_want').

它给出

[('0', 1), ('b9', 2), ('b10', 0)]

对于您的示例2.

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