需要在Java中将字符串分成两部分 [英] Need to split a string into two parts in java

问题描述

我有一个字符串，其中包含一个连续的数字块，然后是一个连续的字符块.我需要将它们分为两部分(一个整数部分和一个字符串).

I have a string which contains a contiguous chunk of digits and then a contiguous chunk of characters. I need to split them into two parts (one integer part, and one string).

我尝试使用String.split("\\D", 1)，但它正在占用第一个字符. 我检查了所有String API，但没有找到合适的方法.

I tried using String.split("\\D", 1), but it is eating up first character. I checked all the String API and didn't find a suitable method.

有什么方法可以做这件事吗?

Is there any method for doing this thing?

推荐答案

使用环顾方法:str.split("(?<=\\d)(?=\\D)")

String[] parts = "123XYZ".split("(?<=\\d)(?=\\D)");
System.out.println(parts[0] + "-" + parts[1]);
// prints "123-XYZ"

\d是数字的字符类； \D是它的否定.因此，此零位匹配断言匹配前一个字符为数字(?<=\d)且后一个字符为非数字(?=\D)的位置.

\d is the character class for digits; \D is its negation. So this zero-matching assertion matches the position where the preceding character is a digit (?<=\d), and the following character is a non-digit (?=\D).

• regular-expressions.info/环顾和
• Java拆分正在吞噬我的角色.
• 有没有办法用String.split()分割字符串并包含定界符?

• Java split is eating my characters.
• Is there a way to split strings with String.split() and include the delimiters?

以下内容也适用:

    String[] parts = "123XYZ".split("(?=\\D)", 2);
    System.out.println(parts[0] + "-" + parts[1]);

这会在我们看到一个数字之前分裂.这与您的原始解决方案更加接近，除了它实际上与非数字字符不匹配之外，不会吃掉"它.另外，它使用的是2中的limit，这确实是您想要的.

This splits just before we see a non-digit. This is much closer to your original solution, except that since it doesn't actually match the non-digit character, it doesn't "eat it up". Also, it uses limit of 2, which is really what you want here.

• String.split(String regex, int limit)
  • If the limit n is greater than zero then the pattern will be applied at most n - 1 times, the array's length will be no greater than n, and the array's last entry will contain all input beyond the last matched delimiter.

  这篇关于需要在Java中将字符串分成两部分的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！