PHP& < noscript>组合以检测浏览器中已启用的JavaScript [英] PHP & <noscript> combination to detect enabled JavaScript in browser
问题描述
这是正确的吗?如果不是，那么正确的语法是什么
Is this correct? If not what is the correct syntax
我是php的新手，因此尝试学习.
I am new to php hence trying to learn.
<?php
// Check browser for JavaScript support
$jsSupport='true'; ?>
<noscript><?php $jsSupport='false'; ?></noscript>
<?php
if ($jsSupport == 'false') {
include ('no-script-layout.php');
} else {
include ('regular-layout.php');
}
?>
还是有更好的方法来解决这个问题?
Or is there a better way to handle this?
推荐答案
<noscript>标签
您可以使用noscript标记向禁用了javascript的浏览器显示内容，也可以将其重定向到另一个页面(例如nojs-version.php).
<noscript> tags
You can use the noscript tags to display content to browsers with javascript disabled or redirect them to another page (a nojs-version.php for example).
<!-- Redirect to another page (for no-js support) (place it in your <head>) -->
<noscript><meta http-equiv="refresh" content="0;url=nojs-version.php"></noscript>
<!-- Show a message -->
<noscript>You don't have javascript enabled! Please download Google Chrome!</noscript>
Modernizr
处理javascript检测(和功能)的更好方法是使用Modernizr: http://modernizr.com
查看以下SO问题:什么是HTML"no-js"的目的上课?
您可以在页面加载时将类no-js添加到您的<body>标记中.然后，当页面加载并且如果启用了javascript时，您可以将no-js替换为js，如下所示:
You could add the class no-js on page load to your <body> tag. Then when the page loads and if javascript is enabled, you can replace the no-js with js like so:
// When the DOM is ready & loaded, do this..
$(document).ready(function(){
// Remove the `no-js` and add the `js` (because JS is enabled (we're using it!)
$('body').removeClass('no-js').addClass('js');
// Assign it to a var so you don't traverse the DOM unnecessarily.
var useJS = $('body').hasClass('js');
if(useJS){
// JS Enabled
}
});
上面的代码是modernizr的工作原理的非常基本的示例.我强烈建议您仅使用它.
The above code is a very basic example of how modernizr works. I would highly recommend just using that.
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