Swift:正确解码不精确的小数 [英] Swift: Decode imprecise decimal correctly

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问题描述

我需要从

I need to decode (Decodable protocol) an imprecise decimal value correctly, from this question I understand how to properly handle the Decimal instantiation, but how can I do this when decoding?

如果尝试将任何数字初始化为字符串

If trying to init any number as a String

if let value = try! container.decode(String.self, forKey: .d) {
    self.taxAmount = Decimal(string: value)
}

我得到Fatal Error: "Expected to decode String but found a number instead."

如果尝试将130.43初始化为小数

And if try to init 130.43 as a Decimal

if let value = try! container.decode(Decimal.self, forKey: .d) {
    //value.description is 130.43000000000002048
    self.d = Decimal(string: value.description)
    //making subtotal to be also 130.43000000000002048 and not 130.43
}

解码时有什么方法可以使用其中一个构造函数吗?

Is there any way to use either of this constructors when decoding?

  • NSDecimalNumber(string: "1.66")
  • NSDecimalNumber(value: 166).dividing(by: 100)
  • Decimal(166)/Decimal(100)
  • Decimal(sign: .plus, exponent: -2, significand: 166)
  • NSDecimalNumber(string: "1.66")
  • NSDecimalNumber(value: 166).dividing(by: 100)
  • Decimal(166)/Decimal(100)
  • Decimal(sign: .plus, exponent: -2, significand: 166)

这是我从外部服务收到的JSON的简化版本:

Here is a simplified version of the JSON I receive from the external service:

{
   "priceAfterTax": 150.00,
   "priceBeforeTax": 130.43,
   "tax": 15.00,
   "taxAmount": 19.57
}

注意:我无法更改接收到的要解码的内容,我只能使用十进制数字.

Note: I can't change what is being received to be decoded, I'm stuck working with decimal numbers.

推荐答案

您可以实现自己的解码方法,并以最多两个小数位数的形式设置double格式,然后使用该字符串初始化您的十进制属性:

You can implement your own decoding method and format your double with maximum two fraction digits and use the string to initialize your decimal properties:

struct Root: Codable {
    let priceAfterTax, priceBeforeTax, tax, taxAmount: Decimal
}


extension Root {
    public init(from decoder: Decoder) throws {
        var container = try decoder.container(keyedBy: CodingKeys.self)

        let priceAfterTaxDouble = try container.decode(Double.self, forKey: .priceAfterTax)
        priceAfterTax = Decimal(string: Formatter.decimal.string(for: priceAfterTaxDouble)!) ?? 0

        let priceBeforeTaxDouble = try container.decode(Double.self, forKey: .priceBeforeTax)
        priceBeforeTax = Decimal(string: Formatter.decimal.string(for: priceBeforeTaxDouble)!) ?? 0

        let taxDouble = try container.decode(Double.self, forKey: .tax)
        tax = Decimal(string: Formatter.decimal.string(for: taxDouble)!) ?? 0

        let taxAmountDouble = try container.decode(Double.self, forKey: .taxAmount)
        taxAmount = Decimal(string: Formatter.decimal.string(for: taxAmountDouble)!) ?? 0
    }
}


extension Formatter {
    static let decimal: NumberFormatter = {
        let formatter = NumberFormatter()
        formatter.numberStyle = .decimal
        formatter.decimalSeparator = "."
        formatter.maximumFractionDigits = 2
        return formatter
    }()
}


let data = Data("""
{
"priceAfterTax": 150.00,
"priceBeforeTax": 130.43,
"tax": 15.00,
"taxAmount": 19.57
}
""".utf8)

let decodedObj = try! JSONDecoder().decode(Root.self, from: data)
decodedObj.priceAfterTax   // 150.00
decodedObj.priceBeforeTax  // 130.43
decodedObj.tax             // 15.00
decodedObj.taxAmount       // 19.57

这篇关于Swift:正确解码不精确的小数的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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