argparse不检查位置参数 [英] argparse doesn't check for positional arguments

问题描述

我正在创建一个脚本，该脚本同时使用argparse的位置参数和可选参数.我已经阅读了Doug的教程和python文档，但是找不到答案.

I'm creating a script that takes both positional and optional arguments with argparse. I have gone through Doug's tutorial and the python Docs but can't find an answer.

parser = argparse.ArgumentParser(description='script to run')
parser.add_argument('inputFile', nargs='?', type=argparse.FileType('rt'),
parser.add_argument('inputString', action='store', nargs='?') 
parser.add_argument('-option1', metavar='percent', type=float, action='store')
parser.add_argument('-option2', metavar='outFile1', type=argparse.FileType('w'),
parser.add_argument('-option3', action='store', default='<10',
args = parser.parse_args()
# rest of script.... blah blah

如您所见，我想要2个位置参数和3个可选参数.但是，当我尝试在终端中运行它时，它不会检查位置信息！ 如果我尝试:python script.py inputfile 如果找不到inputString的值，它将正常运行并在脚本的一半输出错误. 如果我尝试:python script.py xxx;输出为:

As you can see, I want 2 positional and 3 optional arguments. However, when I try to run it in the terminal, it doesn't check for the positionals! If I try: python script.py inputfile it will run normally and output error halfway through the script when it cannot find a value for inputString. If I try: python script.py xxx ; the output is:

usage script.py [-h] [-option1] [-option2] [-option3]

任何人都可以解释为什么它不检查位置参数吗?

Can anyone explain why it doesn't check for the positional arguments?

推荐答案

您的问题是您指定了nargs='?'.从文档:

Your problem is that you're specifying nargs='?'. From the documentation:

'?'.如果可能，将从命令行使用一个参数，并将其作为单个项目产生.如果不存在命令行参数，则将生成默认值.

'?'. One argument will be consumed from the command line if possible, and produced as a single item. If no command-line argument is present, the value from default will be produced.

如果省略了nargs='?'，则将需要该参数，如果未提供，则argparse将显示错误.如果action='store'(默认值)，则使用单个参数.

If you leave out the nargs='?' then the argument will be required, and argparse will display an error if it is not provided. A single argument is consumed if action='store' (the default).

您也可以指定nargs=1;不同之处在于，这将产生一个包含一个项目的列表，而不是该项目本身.有关使用nargs的更多方法，请参见文档.

You can also specify nargs=1; the difference is that this produces a list containing one item, as opposed to the item itself. See the documentation for more ways you can use nargs.

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