如何在phar文件代码中获取.phar文件真实目录? [英] how to get a .phar file real directory within the phar file code?

问题描述

我试图创建一个php可执行文件(一个phar文件)以生成一些文件，并且我想知道如何获取phar文件的真实路径(在phar文件代码内).

I am trying to create a php executable (a phar file) for generating some files, and I would like to know how to get the real path of the phar file (within the phar file code).

我想做的是在phar文件的同一级别中创建一个文件夹，然后在其中创建新文件，但是realpath(__DIR__.'/../')似乎不起作用.

What I want to do is to create a folder in the same level of the phar file and create the new files there, but realpath(__DIR__.'/../') does not seem to work.

谢谢

推荐答案

如 https://stackoverflow.com/a/28775172/282601 __FILE__常量具有以下方案的完整路径:

As shown in https://stackoverflow.com/a/28775172/282601 the __FILE__ constant has the full path with the scheme:

phar:///home/cweiske/Dev/test/phar/test.phar/path/to/foo.php

__DIR__与之类似:

phar:///home/cweiske/Dev/test/phar/test.phar/path/to

因此，在调用realpath(__DIR__)时，您仍然具有phar://前缀，可防止您加载文件.

So when calling realpath(__DIR__) you still have the phar:// prefix that prevents you from loading the file.

您必须删除phar://方案以及.phar内部文件的路径，才能使用__DIR__获取phar位置.

You have to remove the phar:// scheme as well as the path of the file inside the .phar to get the phar location with __DIR__.

Phar::running(false) 容易得多，它只是返回路径:

Much easier is Phar::running(false), which simply returns the path:

/home/cweiske/Dev/test/phar/test.phar

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