反向preg_replace [英] Reverse preg_replace

问题描述

我有这样的正则表达式:

I have regex like this:

^page/(?P<id>\d+)-(?P<slug>[^\.]+)\.html$

和一个数组:

$args = array(
    'id' => 5,
    'slug' => 'my-first-article'
);

我想要功能:

my_function($regex, $args)

这将返回此结果:

page/5-my-first-article.html

如何实现?

类似于 https://docs.djangoproject.com/en/dev之类的东西/ref/urlresolvers/#reverse

推荐答案

有趣的挑战，我编写了一些适用于此示例的代码，请注意，要使此代码起作用，您需要PHP 5.3 +:

Interesting challenge, I coded something that works for this sample, note that you need PHP 5.3+ for this code to work:

$regex = '^page/(?P<id>\d+)-(?P<slug>[\.]+)\.html$';
$args = array(
    'id' => 5,
    'slug' => 'my-first-article'
);

$result = preg_replace_callback('#\(\?P<(\w+)>[^\)]+\)#', function($m)use($args){
    if(array_key_exists($m[1], $args)){
        return $args[$m[1]];
    }
}, $regex);

$result = preg_replace(array('#^\^|\$$#', '#\\\\.#'), array('', '.'), $result); // To remove ^ and $ and replace \. with .
echo $result;

输出: page/5-my-first-article.html

在线演示 .

Online demo.

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