PHP中的数字反转未显示正确的输出 [英] Reverse of number in PHP not showing correct output

问题描述

我制作了一个程序来反转数字，但是每次将0附加到结果之后.

I have made a program to reverse the number but every time 0 gets appended to the result.

$num = 675;
$rev = 0;

while($num > 0) {
$temp = $num % 10;
$rev = ($rev *  10) + $temp;
$num = (int) $num / 10;
}

echo $rev;   //result is 5760

推荐答案

您的问题是这一行:

$num = (int) $num / 10;

与以下相同:

$num = ((int) $num) / 10;

因此它实际上不会强制转换结果.使用多余的括号:

so it doesn't actually cast the result. Use the extra parentheses:

$num = (int) ($num / 10);

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