将值传递给php中的包含文件 [英] Pass value to an include file in php

问题描述

如何将参数传递到包含文件中?我尝试了以下操作，但不起作用.

How do you pass a parameter into an include file? I tried the following but it doesn't work.

包括"myfile.php?var = 123";

include "myfile.php?var=123";

在myfile.php中，我尝试使用$ _GET ["var"]检索参数.

and in myfile.php, I try to retrieve the parameter using $_GET["var"].

include "myfile.php?var=123";将不起作用. PHP搜索具有此确切名称的文件，但不解析参数

include "myfile.php?var=123"; will not work. PHP searches for a file with this exact name and does not parse the parameter

为此，我也这样做了:

include "http://MyGreatSite.com/myfile.php?var=123";，但它也不起作用.

有任何提示吗?谢谢.

推荐答案

将所包含文件的内容包装在一个或多个函数中.这样您就可以做到

Wrap the contents of the included file in a function (or functions). That way you can just do

include "myfile.php";
myFileFunction($var1, $var2);

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