从另一个php执行php文件 [英] Execute php file from another php

问题描述

我想调用一个像这样开始的PHP文件

I want to call a PHP file that starts like

<?php
function connection () {
   //Statements
}

我是这样从PHP调用的:

I call from the PHP like this:

<?php
exec ('/opt/lampp/htdocs/stuff/name.php');
?>

我得到:

line1-> cannot open ?: No such file
line 3 //Connection: not found
line 4 Syntax errror: "("

为什么这不能正确执行name.php文件?

Why doesn't this correctly execute the name.php file?

推荐答案

它正在尝试将其作为shell脚本运行，该脚本将您的<?php令牌解释为bash，这是语法错误.只需使用include()或其朋友之一:

It's trying to run it as a shell script, which interprets your <?php token as bash, which is a syntax error. Just use include() or one of its friends:

例如，在a.php中放置:

<?php
print "one";
include 'b.php';
print "three";
?>

在b.php中放置:

<?php
print "two";
?>

打印:

eric@dev ~ $ php a.php
onetwothree

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