用TWIG加载远程文件 [英] Load Remote File with TWIG
问题描述
在Symfony 2.3中使用Twig，我需要能够在Twig模板中选择远程资产.
Using Twig in Symfony 2.3 I need to be able to select remote assets inside a twig template.
所以我有一个带有这样的正文块的树枝模板:
So I have a twig template with a body block like this:
{% block body %}
{% include 'http://asset.remotelocation.co.uk/template.html.twig' %}
{% endblock %}
，如您所见，它试图包含一个远程树枝模板.这是可能的，因为symfony只是错误地指出找不到模板?
and as you can see its trying to include a remote twig template. Is this possible as symfony just errors saying it cant find the template?
在我的代码中，树枝模板的位置是正确的，因为我可以在浏览器中浏览到模板URL.
The twig template location is correct in my code as I can browse to the template url in my browser.
任何帮助都倍受赞赏. =)
Any help is much appeciated. =)
P.S远程位置只是我们拥有共享资产的其他Web服务器之一.
P.S the remote location is just one of our other webserver where we hold shared assets.
推荐答案
您可以创建一个函数，该函数将为您下载该文件并使其可用于树枝.
You can create a function that will download this file for you, and make it available for twig.
想法:
- 您创建目录
app/Resources/views/temp，因此可以在:temp:file.html.twig中访问树枝文件
- 在树枝文件中，您将使用
remote_file()函数包装第一个include的参数 - 您的文件将通过您的函数在
temp目录中以随机名称 下载.
- 您的函数将返回一条细枝路径以本地访问文件(
:temp:file.html.twig) - 不要忘记自动执行一些操作以清除太旧的临时文件！ (一个cron吗?)
- You create a directory
app/Resources/views/temp, so a twig files can be accessed at:temp:file.html.twig - In your twig file, you'll use a
remote_file()function to wrap the firstinclude's argument - Your files will be downloaded by your function inside
tempdirectory with a random name - your function will return a twig path to access the file locally (the
:temp:file.html.twig) - don't forget to automate something to clear too old temp files! (a cron?)
创建一个临时目录，以便您的symfony目录树如下所示:
Create a temp directory so that your symfony directory tree looks like this:
在包中，创建一个Twig\Extension目录.在此处，使用以下代码创建一个RemoteFileExtension.php文件.注意:别忘了用您的命名空间替换我的命名空间.
Inside your bundle, create a Twig\Extension directory. There, create a RemoteFileExtension.php file with the following code. Note: don't forget to replace my namespaces by yours.
<?php
namespace Fuz\TestBundle\Twig\Extension;
use Symfony\Component\HttpKernel\KernelInterface;
class RemoteFileExtension extends \Twig_Extension
{
private $kernel;
public function __construct(KernelInterface $kernel)
{
$this->kernel = $kernel;
}
public function getFunctions()
{
return array(
'remote_file' => new \Twig_Function_Method($this, 'remote_file'),
);
}
public function remote_file($url)
{
$contents = file_get_contents($url);
$file = $this->kernel->getRootDir() . "/Resources/views/temp/" . sha1($contents) . '.html.twig';
if (!is_file($file))
{
file_put_contents($file, $contents);
}
return ':temp:' . basename($file);
}
public function getName()
{
return 'remote_file';
}
}
在您的services.yml配置文件中，添加以下内容:
Inside your services.yml configuration file, add the following:
在parameters以下:
fuz_tools.twig.remote_file_extension.class: Fuz\TestBundle\Twig\Extension\RemoteFileExtension
在services以下:
fuz_tools.twig.remote_file_extension:
class: '%fuz_tools.twig.remote_file_extension.class%'
arguments: ['@kernel']
tags:
- { name: twig.extension }
测试！
我创建了一个现有的http://localhost:8888/test.html.twig.它仅包含:
Hello, {{ name }}!
在我的应用程序中，我放置了以下行:
Inside my application, I put the following line :
{% include remote_file('http://localhost:8888/test.html.twig') with {'name': 'Alain'} %}
运行代码时，我得到:
您应该考虑将树枝文件包含在您的应用程序中.细枝文件不是资产，因为Symfony2需要使用一些逻辑，一些优化等来解释它.您实际上在做什么，相当于在执行之前远程包含一个PHP文件，我认为这是一种奇怪的体系结构.
You should consider that a twig file takes part of your application. A twig file is not an asset, as it needs to be intepreted by Symfony2, with some logic, with some optimizations and so on. What you're doing actually is comparable to a remote include of a PHP file before executing it, strange architecture I think.
无论如何，您的问题很有趣，祝您实施顺利.
Anyway, your question was interesting, good luck for your implementation.
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