从PHP中的实例调用静态方法，将来弃用吗? [英] Call static method from instance in PHP, future deprecation?

问题描述

虽然我知道在静态上下文中调用方法时$this变量不可用，以帮助将我的应用程序组件彼此分离，但我认为从实例中调用静态方法是有意义的.例如:

While I understand the $this variable is not available when a method is called in a static context, to assist in decoupling my application components from one-another I figured it would make sense to call static methods from an instance. For example:

class MyExample{
    private static $_data = array();
    public static function setData($key, $value){
        self::$_data[$key] = $value;
    }
    // other non-static methods, using self::$_data
}

// to decouple, another class or something has been passed an instance of MyExample
// rather than calling MyExample::setData() explicitly
// however, this data is now accessible by other instances
$example->setData('some', 'data');

是否有计划弃用这种功能，或者我是否期望对这种功能的支持?我与error_reporting(-1)一起使用以确保非常严格的开发环境，并且到目前为止还没有任何问题( PHP 5.3.6 )，但是我知道相反的情况不再得到支持；也就是说，实例方法被静态调用.

Are there plans to deprecate this sort of functionality, or am I right to expect support for this going forward? I work with error_reporting(-1) to ensure a very strict development environment, and there aren't any issues as of yet (PHP 5.3.6) however I am aware of the reverse becoming unsupported; that is, instance methods being called statically.

推荐答案

来自 Php文档:

不能通过实例化访问声明为静态的属性 类对象(尽管静态方法可以).

A property declared as static can not be accessed with an instantiated class object (though a static method can).

所以我认为它将得到长期支持.

So I think it will be forward-supported for a long time.

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