在ListView中显示ArrayList中的项目包含2 textviews [英] Displaying ArrayList items in ListView contains 2 textviews

问题描述

我要显示在ListView中ArrayList的项目由具有2个不同的textViews。
 我使用ListViewCustomAdapter和getView（），getItem（）时...的方法有哪些。

I want to display the arrayList items in ListView which is having 2 different textViews. I am using ListViewCustomAdapter and getView(),getItem()... methods are there.

这是我的code：
MyCustom.java：

This is my code: MyCustom.java:

public class MyCustom extends BaseAdapter {
  public Activity context;  
  public LayoutInflater inflater; 
  ArrayList mylist;

  public MyCustom(Activity context,ArrayList viewList) {
        super();
        this.context=context;
        this.mylist=viewList;

        inflater=(LayoutInflater)context.getSystemService(context.LAYOUT_INFLATER_SERVICE);

  }

  @Override
  public int getCount() {
    // TODO Auto-generated method stub
    return mylist.size();
  }

  @Override
  public Object getItem(int position) {
    // TODO Auto-generated method stub
    return position;
  }

  @Override
  public long getItemId(int position) {
    // TODO Auto-generated method stub
    return position;
  }


  @Override
  public View getView(int position, View convertView, ViewGroup parent) {
    // TODO Auto-generated method stub

    View List;
    if(convertView==null)
    {
        List=new View(context);
        LayoutInflater mLayoutinflater=(LayoutInflater)context.getSystemService(context.LAYOUT_INFLATER_SERVICE);
        List=mLayoutinflater.inflate(R.layout.listitem_row, parent, false);
    }
    else
    {
        List=(View)convertView;

    }

    TextView t1=(TextView)List.findViewById(R.id.txtViewTitle);
    t1.setText((CharSequence) mylist.get(position));

    TextView t2=(TextView)List.findViewById(R.id.txtViewDescription);
    t2.setText(mylist.get(position).toString());


    return List;
  }
}

以上code，有如下所述的问题。
这将是在ListView中既TextView显示该ArrayList项相同。
例如：
MYLIST = ['A1'，'A2'，'B1'，'B2']
这是我的ArrayList和传递给MyCustomAdapter。

Above code, there is problem as mentioned below. This will be display the arrayList items as same in both the textviews in ListView. Ex: mylist=['a1','a2','b1','b2'] this is my arraylist and passing to MyCustomAdapter.

在运行时，'A1'将被同时显示在textviews.and等等。

At runtime, 'a1' will be displayed in both the textviews.and so on.

我要显示textView1A1和A2是textView2 ..和B1是...等等...

I want to display 'a1' in textView1 and 'a2' is in textView2.. and b1 is .. so on...

我想我可能在具有的getItem问题（），getItemId（），getCount将（）方法..
请帮我...

I think i may have problem in getItem(), getItemId(), getcount() method.. PLEASE HELP ME...

推荐答案

它从你的问题清楚[A1，A2，B1，B2，C1，C2 ...]
为

Its clear from your question that you want to display [a1, a2, b1, b2, c1, c2...] as

a1a2
b1b2
c1c2

所以你需要改变你的code到以下几点：

so you need to change your code to following:

@Override
public int getCount() {
    // TODO Auto-generated method stub
    if(myList.size()%2==0)
        return mylist.size()/2;
    else
        return myList.size()/2+1;
}

和getView方法如下：

and getView method as below:

@Override
public View getView(int position, View convertView, ViewGroup parent) {
    // TODO Auto-generated method stub

    View List;
    if(convertView==null)
    {
        List=new View(context);
        LayoutInflater mLayoutinflater=(LayoutInflater)context.getSystemService(context.LAYOUT_INFLATER_SERVICE);
        List=mLayoutinflater.inflate(R.layout.listitem_row, parent, false);
    }
    else
    {
        List=(View)convertView;

    }

    TextView t1=(TextView)List.findViewById(R.id.txtViewTitle);
    t1.setText((CharSequence) mylist.get(position*2));


    TextView t2=(TextView)List.findViewById(R.id.txtViewDescription);
    if(position*2<getCount())
           t2.setText(mylist.get(position*2+1).toString());


    return List;
}

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