生成随机数而无需连续重复 [英] generating random numbers without consecutive repetition

问题描述

如何以不连续产生两次相同的数字的方式从0-4产生随机整数?例如，如果3是第一次生成的数字，则0、1、2、4将是第二次随机生成的可能数字.如果第二次生成2，则0、1、3、4将是第三次随机生成的可能数字，依此类推.

How can I generate random integers from 0 - 4 in such a way that the same number is not generated twice consecutively? For example, if 3 is the number that is generated the first time then 0,1,2,4 will be the possible numbers for random generation the second time. If 2 is generated the second time then 0,1,3,4 will be the possible numbers for random generation the third time and so on.

推荐答案

int oldrand = <prior random number>;
int adder = randomNumberGenerator() % 4;
int newrand = (oldrand + adder + 1) % 5;

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