如何通过从字母数字字符中采样来创建随机字符串? [英] How do I create a random String by sampling from alphanumeric characters?

问题描述

我尝试编译以下代码:

extern crate rand; // 0.6
use rand::Rng;

fn main() {
    rand::thread_rng()
        .gen_ascii_chars()
        .take(10)
        .collect::<String>();
}

但是cargo build说:

warning: unused import: `rand::Rng`
 --> src/main.rs:2:5
  |
2 | use rand::Rng;
  |     ^^^^^^^^^
  |
  = note: #[warn(unused_imports)] on by default

error[E0599]: no method named `gen_ascii_chars` found for type `rand::prelude::ThreadRng` in the current scope
 --> src/main.rs:6:10
  |
6 |         .gen_ascii_chars()
  |          ^^^^^^^^^^^^^^^

Rust编译器要求我删除use rand::Rng;子句，同时抱怨没有gen_ascii_chars方法. 我希望Rust只使用rand::Rng特质，而不提供这种矛盾的错误消息.我该怎么走?

The Rust compiler asks me to remove the use rand::Rng; clause, at the same time complaining that there is no gen_ascii_chars method. I would expect Rust to just use rand::Rng trait, and to not provide such a contradictory error messages. How can I go further from here?

推荐答案

如从0.6.0开始，代码应为:

As of 0.6.0, the code should be:

extern crate rand;

use rand::Rng; 
use rand::distributions::Alphanumeric;

fn main() {
    rand::thread_rng()
        .sample_iter(&Alphanumeric)
        .take(10)
        .collect::<String>(); 
}

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