python中的random() [英] random() in python

问题描述

在python中，函数random()均匀地在半开放范围[0.0，1.0)中生成一个随机浮点数.原则上，它可以产生0.0(即零)和1.0(即1)吗?实际情况是什么?

In python the function random() generates a random float uniformly in the semi-open range [0.0, 1.0). In principle can it ever generate 0.0 (i.e. zero) and 1.0 (i.e. unity)? What is the scenario in practicality?

推荐答案

0.0可以生成； 1.0不能(因为它不在范围内，因此)与[相对).

0.0 can be generated; 1.0 cannot (since it isn't within the range, hence the ) as opposed to [).

生成0.0的概率等于生成该范围内任何其他数字的概率，即1/X，其中X是不同可能结果的数量.对于标准的无符号双精度浮点，这通常意味着53位分数部分，对于2 ^ 53种可能的组合，导致产生(c ^> 1)的机会是((2 ^ 53)).

The probability of generating 0.0 is equal to the probability of generating any other number within that range, namely, 1/X where X is the number of different possible results. For a standard unsigned double-precision floating point, this usually means 53 bits of fractional component, for 2^53 possible combinations, leading to a 1/(2^53) chance of generating exactly 0.0.

因此，尽管它有可能完全返回0.0，但您不太可能很快看到它-但也不太可能看到您可能预先选择的任何其他特定值.

So while it's possible for it to return exactly 0.0, it's unlikely that you'll see it any time soon - but it's just as unlikely that you'd see exactly any other particular value you might choose in advance.

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