Google pydrive将文件上传到特定文件夹 [英] Google pydrive uploading a file to specific folder
本文介绍了Google pydrive将文件上传到特定文件夹的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试将文件上传到我的Google驱动器,下面的代码有效. 如何指定要上传到即驱动器的文件夹-与我共享的文件夹-csvFolder
I am trying to upload a file to my Google drive, the code below works. How can I specify to which folder to upload to i.e drive---shared with me--csvFolder
from pydrive.auth import GoogleAuth
from pydrive.drive import GoogleDrive
gauth = GoogleAuth()
gauth.LocalWebserverAuth()
drive = GoogleDrive(gauth)
file2 = drive.CreateFile()
file2.SetContentFile('new_test.csv')
file2.Upload()
推荐答案
- 您要使用pydrive将文件上传到Google云端硬盘中的特定文件夹.
如果我的理解是正确的,那么该修改如何?
If my understanding is correct, how about this modification?
file2 = drive.CreateFile()
收件人:
file2 = drive.CreateFile({'parents': [{'id': '### folder ID ###'}]})
- 请像上面一样设置文件夹ID.
如果这不是您想要的结果,我表示歉意.
If this was not the result you want, I apologize.
要从文件夹名称将文件上传到特定文件夹时,如何进行此修改?
When you want to upload a file to the specific folder from the folder name, how about this modification?
file2 = drive.CreateFile()
file2.SetContentFile('new_test.csv')
file2.Upload()
收件人:
folderName = '###' # Please set the folder name.
folders = drive.ListFile(
{'q': "title='" + folderName + "' and mimeType='application/vnd.google-apps.folder' and trashed=false"}).GetList()
for folder in folders:
if folder['title'] == folderName:
file2 = drive.CreateFile({'parents': [{'id': folder['id']}]})
file2.SetContentFile('new_test.csv')
file2.Upload()
获取文件夹ID的替代方法
您可以使用以下代码段来打印文件和/或文件夹ID
Alternative to get folder ID
You can use the following snippet to print files and or folders ID
fileList = drive.ListFile({'q': "'root' in parents and trashed=false"}).GetList()
for file in fileList:
print('Title: %s, ID: %s' % (file['title'], file['id']))
# Get the folder ID that you want
if(file['title'] == "To Share"):
fileID = file['id']
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