python套接字GET [英] python socket GET

问题描述

在堆栈溢出的其他帖子中，这应该可以正常工作

From the other posts on stack overflow this should be working

import socket

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)                 

s.connect(("www.cnn.com" , 80))
s.sendall("GET / HTTP/1.1\r\n")
print s.recv(4096)
s.close

，但是由于某种原因，它只是挂起(在recv)并且从不打印.我知道对www.cnn.com的请求将对数据进行分块处理，但是我至少应该从recv中读取某些内容，对吧?

but for some reason it just hangs (at recv) and never prints. I know that a request to www.cnn.com will chunk it's data but I should at least read something from recv, right?

p.s.我知道这不是最好的方法，并且那里有类似httplib和urllib2的库，但是我不能将它们用于该项目(用于学校).我必须使用socket库

p.s. I know this isn't the best way to do it and that there are library like httplib and urllib2 out there, but I can't use those for this project (it's for school). I have to use the socket library

推荐答案

您忘了在请求行之后发送空白行:

You forgot to send a blank line after your request line:

s.sendall("GET / HTTP/1.1\r\n\r\n")

此外，HTTP 1.1指定您应添加Host标头字段rel ="noreferrer"> HTTP 1.1 RFC中的主机部分.

Furthermore, HTTP 1.1 specifies you should add the Host header field as documented in the Host section in the HTTP 1.1 RFC.

s.sendall("GET / HTTP/1.1\r\nHost: www.cnn.com\r\n\r\n")

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