迅速.从整数获取二进制字符串 [英] Swift. Get binary string from an integer

问题描述

我有二进制0000010，它表示为一个整数数组.从此二进制文件中，我得到一个Integer:

I have binary 0000010 which is represented as an array of ints. From this binary I get an Integer:

let number = Int32([0, 0, 0, 0, 0, 1, 0].reduce(0, combine: {$0*2 + $1}))//数字= 2

但是当我想进行逆运算以获得String时:

but when I want to inverse operation to get a String:

let binaryString = String(2, radix: 2)//binaryString = "10"

let binaryString = String(2, radix: 2) // binaryString = "10"

看来基数会削减一些位(如果它们为0)，又如何返回5个零?

So seems radix cuts some bits if they are 0, how to return 5 more zeros?

推荐答案

let binaryString = String(2, radix: 2)
let other = String(count: 8 - binaryString.characters.count, repeatedValue: Character("0")) + binaryString

这篇关于迅速.从整数获取二进制字符串的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！