改变路径或完善 [英] Change path or refinement

问题描述

我想将一个块内的a/b更改为a/c(甚至可能是a)

I want to change the a/b inside a block to a/c (or possibly even a)

我通常这样做的方法是使用change:

The normal way I'd do this is with change:

test: [a/b]
change test/1 'c

，但只会更改第一部分，即a到c:

but it only changes the first part, i.e. a to c:

>> test
== [c/b]

也无法使用test/2访问路径:

>> reduce [test/1 test/2]
== [a/b none]

推荐答案

这里有两点需要注意:

首先，path!是一个序列，因此在这种情况下是嵌套序列.必须实际访问 second 元素内部 first 元素:

First, path! is a series, so in this case, a nested series. Have to actually access the second element inside the first element:

>> test: [a/b] test/1/2
== b

第二，使用series的属性，使它们的行为类似于指针并访问next元素，而不是直接访问

Secondly, use the property of series that make them behave like pointers and access the next element, instead of accessing it directly:

>> next test/1
== b

因此代码变为:

>> change next test/1 'c test
== [a/c]

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