R中的等级和顺序 [英] rank and order in R

问题描述

我无法理解R函数rank和R函数order之间的区别.它们似乎产生相同的输出:

i am having trouble understanding the difference between the R function rank and the R function order. they seem to produce the same output:

> rank(c(10,30,20,50,40))
[1] 1 3 2 5 4
> order(c(10,30,20,50,40))
[1] 1 3 2 5 4

有人可以帮我一下吗? 谢谢

Could somebody shed some light on this for me? Thanks

推荐答案

> set.seed(1)
> x <- sample(1:50, 30)    
> x
 [1] 14 19 28 43 10 41 42 29 27  3  9  7 44 15 48 18 25 33 13 34 47 39 49  4 30 46  1 40 20  8
> rank(x)
 [1]  9 12 16 25  7 23 24 17 15  2  6  4 26 10 29 11 14 19  8 20 28 21 30  3 18 27  1 22 13  5
> order(x)
 [1] 27 10 24 12 30 11  5 19  1 14 16  2 29 17  9  3  8 25 18 20 22 28  6  7  4 13 26 21 15 23

rank返回一个带有每个值秩"的向量.在第一个位置的数字是第9个最低的数字. order返回将初始向量x按顺序排列的索引.

rank returns a vector with the "rank" of each value. the number in the first position is the 9th lowest. order returns the indices that would put the initial vector x in order.

x的第27个值是最低的，因此27是order(x)的第一个元素-如果您查看rank(x)，则第27个元素是1.

The 27th value of x is the lowest, so 27 is the first element of order(x) - and if you look at rank(x), the 27th element is 1.

> x[order(x)]
 [1]  1  3  4  7  8  9 10 13 14 15 18 19 20 25 27 28 29 30 33 34 39 40 41 42 43 44 46 47 48 49

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