网址的PHP scandir [英] PHP scandir of an url

问题描述

如何将scandir与URL结合使用.现在看来，PHP无法将URL视为URL.有没有办法在scandir中使用URL?

How can I use scandir with an URL. Now it looks like PHP doesn't see the URL as an URL. Is there a way to use an URL in scandir?

<form action="new_exercise.php?id=<?php echo $new_id; ?>" method="post">
        <input class="" type="text" name="name_exe" required placeholder="Project naam">
        <select name="audio" required>
          <option></option>
          <?php
          $path = 'URL comes here';
          $results = scandir($path);
          foreach ($results as $result) {
              if ($result === '.' or $result === '..') continue;

              if (is_dir($path . '/' . $result)) {
                  echo "<option>" . $result . "</option>";
              }
          }
          ?>
        <select>
        <input class="btn-success" type="submit" name="submit" value="Maak nieuwe opdracht">
    </form>

推荐答案

这是不可能的. scandir()和许多其他文件操作仅在本地工作.

This is not possible. scandir() and many other file operations only work local.

如果要获取远程服务器上的文件列表，则需要在服务器上返回该文件列表的脚本/API.

If you want to get a list of files on a remote server then you need a script/API on the server that will return that file list.

试想一下，如果您可以读取远程计算机上的所有文件和目录，将会发生什么?安全性确实会受到损害.

Just imagine what would happen if you could read all files and directories on a remote machine? Security would be realy compromised.

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