从目录读取* .csv文件并显示每个文件的内容失败 [英] Reading *.csv files from directory and showing the content of each file fails

问题描述

我需要阅读文件夹并打开/输出csv数据的帮助，我使用了其他人写的示例，但没有一个对我有用.

I need help with reading the folder and opening / outputting the csv data, I have used examples other people have written but none of them have worked for me.

我目前所拥有的是这个，但是它不输出文件:

What I currently have is this, but it doesn't output the files:

$files = scandir($PathToCreate.$version."/"); //scan the folder
foreach($files as $file) { //for each file in the folder

//The following is another example I found but does not output anything I just need to open each file and be able to output / target specific data

$csv = array();
$lines = file($file, FILE_IGNORE_NEW_LINES);

foreach ($lines as $key => $value)
{
    $csv[$key] = str_getcsv($value);
} 
print_r($csv)

}

推荐答案

这应该对您有用:

(在这里，我首先使用*.csv的所有文件. > glob() .此后，我循环浏览每个文件，并使用 fopen() 和 fgetcsv() .)

(Here I first grab all files out of the directory which have the extension *.csv with glob(). After this I loop through each file and read it with fopen() and fgetcsv().)

<?php

    $files = glob("$PathToCreate$version/*.csv");

    foreach($files as $file) {

        if (($handle = fopen($file, "r")) !== FALSE) {
            echo "<b>Filename: " . basename($file) . "</b><br><br>";
            while (($data = fgetcsv($handle, 4096, ",")) !== FALSE) {
                echo implode("\t", $data);
            }
            echo "<br>";
            fclose($handle);
        } else {
            echo "Could not open file: " . $file;
        }

    }

?>

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