我可以通过API从Google幻灯片获取演讲者备注吗? [英] Can I get speaker notes from Google Slides by API?

问题描述

我想通过API从Google幻灯片获取演讲者注释，但是找不到演讲者注释的任何字段.

I want to get speaker notes from Google Slides by API, but I could not find any fields for speaker notes.

供参考:方法: presentations.pages.get

什么是做到这一点的好方法?

What would be a good way to do this?

推荐答案

在没有API的情况下，我不建议这是一种好的方法.实际上，这是可怕的.但是在这里.如果您绝对必须这样做.它也可能有点苦涩.

In the absence of the API, I wouldn't suggest this is a good way of doing it. In fact it is horrible. But here it is. If you absolutely had to do it. It is likely a bit flakey too.

步骤是:

1. 通过Drive API将演示文稿导出为PowerPoint .pptx文件
2. 解压缩文件-这是一个zip文件，其中包含带有XML文件的目录结构.
3. 识别演讲者注释文件并根据您的要求进行处理(例如，提取所有文本，或处理XML等).

丑陋吧?这是Apps脚本中的示例:

Ugly right? Here's an example in Apps Script:

1. 在脚本(资源>高级Google服务)中的Advanced Services中启用 Drive API .

1. Enable Drive API in Advanced Services within your script (Resources > Advanced Google Services).

function example() {
  // Print out the speaker notes
  Logger.log(getNotes('123abc......asd'));
}

// Returns an array of strings, one string per slide
// representing the speaker notes.
function getNotes(presentationId) {
  //DriveApp.createFile();
  var notesRegex = /ppt\/notesSlides\/notesSlide\d+\.xml/;

  var url = 'https://www.googleapis.com/drive/v2/files/' + presentationId +
    '/export?mimeType=application%2Fvnd.openxmlformats-officedocument.presentationml.presentation';
  var options = {
    headers: {
      Authorization : 'Bearer ' + ScriptApp.getOAuthToken()
    }
  };
  var response = UrlFetchApp.fetch(url, options);

  var zipBlob = Utilities.newBlob(response.getContent(), 'application/zip');
  var data = Utilities.unzip(zipBlob);

  var notes = [];
  for (var i = 0; i < data.length; i++) {
    if (notesRegex.test(data[i].getName())) {

      // Example simply extracts text from speaker notes
      // You could do something more complex.
      notes.push(extractTextFromXml(data[i].getDataAsString()));
    }
  }
  return notes;
}

function extractTextFromXml(xml) {
  var doc = XmlService.parse(xml);
  var root = doc.getRootElement();
  var ns = root.getNamespace('a');

  var text = [];

  function walkNode(node) {
    if (node.getText()) {
      text.push(node.getText());
    }
    var children = node.getChildren();
    if (children.length) {
      children.forEach(function(child) {
        walkNode(child);
      });
    }
  }
  walkNode(root);
  return text.join('\n');
}

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