xslt排序列表,如果倍数仅打印一次 [英] xslt ordering list and if multiples only print word once

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问题描述

我有以下下拉列表

<xsl:if test="bankguarantee!=0">
            <li style="font-family:Arial,Arial MT,Luxi Sans,Verdana; font-size:10pt; margin:0cm 0cm 0pt; ">
                <p style="font-family:Arial,Arial MT,Luxi Sans,Verdana; font-size:10pt; margin:0cm 0cm 0pt; ">
                    <span style="font-family:Arial,Arial MT,Luxi Sans,Verdana; font-size:11.0pt; ">The terms and conditions of <xsl:if test="bankguarantee='1'">the </xsl:if>
            <xsl:if test="bankguarantee!='1'">each </xsl:if>
    <xsl:for-each select="bankguarantees/bankguaranteedata">
    <xsl:if test="producttypes/option[@id='A']='selected'">A</xsl:if>
    <xsl:if test="producttypes/option[@id='B']='selected'">B</xsl:if>
    <xsl:if test="producttypes/option[@id='C']='selected'">C</xsl:if>
    <xsl:if test="producttypes/option[@id='D']='selected'">D</xsl:if>
    <xsl:if test="producttypes/option[@id='E']='selected'">E</xsl:if>
    <xsl:if test="producttypes/option[@id='F']='selected'">F</xsl:if>
    <xsl:if test="producttypes/option[@id='G']='selected'">G</xsl:if>
    <xsl:if test="producttypes/option[@id='H']='selected'"><xsl:value-of select="otherprodtypebox"/></xsl:if>
  <xsl:if test="position()!=last() and position()!=last()-1">
    <xsl:text>, </xsl:text>
  </xsl:if>
  <xsl:if test="position()=last()-1">
    <xsl:text> and </xsl:text>
  </xsl:if>
  <xsl:if test="position()=last()">
    <xsl:text></xsl:text>
  </xsl:if></xsl:for-each>
</xsl:if>

和以下xml

<producttypes>
                <option id="A">selected</option>
                <option id="B"/>
                <option id="C"/>
                <option id="D"/>
                <option id="E"/>
                <option id="F"/>
                <option id="G"/>
                <option id="H"/>
            </producttypes>
        <otherprodtypebox/>

目前基本上一切正常,但我想避免出现倍数,而将所有其他框放在末尾.这些屏幕可能有99个.

Basically all works ok at the moment but I want to avoid multiples occurring and to put all the other boxes at the end. There can be 99 of these screens.

此刻,我选择5个选项,我可以得到A,B,B,otherbox和otherbox

At the moment say I select 5 options I could get A, B, B, otherbox and otherbox

如果要多次选择A,我希望它只显示A,并且所有给G的字母都相同

I want it to have if A is selected more than once only display A and the same for all letters to G

问题与H处的另一个框一起出现,该框可以有多个倍数

The issue comes with the other box at H which can have multiples

所以你可以拥有

A,B,C,D,E,F,G,H,H,H,H和H

A, B, C, D, E, F, G, H, H, H, H AND H

我希望这是有道理的,任何解决方案都将受到赞赏.

I hope this makes sense and any solutions very much appreciated.

重要的是要注意为每个屏幕创建的XML,所以我可以有99种不同的XML,每次都选择不同的内容.这是每个部分都比较棘手的地方.也许它可以检测是否选择了大于1的A.谢谢

N.B. Important to note the XML is created for each screen so I could have 99 different XMLs with something different selected everytime. this is where the for-each part is tricky. maybe it can detect if more than 1 of A is selected. thanks

推荐答案

如何将其添加到XSLT文件顶部附近:

How about adding this near the top of the XSLT file:

<xsl:key name="productOption" match="producttypes/option[. = 'selected']" use="@id"/>

,并用以下for-each循环替换您的for-each循环:

and replacing your for-each loop with this for-each loop:

  <xsl:for-each 
   select="bankguarantees/bankguaranteedata/producttypes/option[generate-id(.) = generate-id(key('productOption', @id)[1]) or @id = 'H']">
    <xsl:sort select="count(preceding-sibling::option)" data-type="number" />
    <xsl:if test="@id = 'A'">A</xsl:if>
    <xsl:if test="@id = 'B'">B</xsl:if>
    <xsl:if test="@id = 'C'">C</xsl:if>
    <xsl:if test="@id = 'D'">D</xsl:if>
    <xsl:if test="@id = 'E'">E</xsl:if>
    <xsl:if test="@id = 'F'">F</xsl:if>
    <xsl:if test="@id = 'G'">G</xsl:if>
    <xsl:if test="@id = 'H'">
      <xsl:value-of select="../../otherprodtypebox"/>
    </xsl:if>
    <xsl:if test="position()!=last() and position()!=last()-1">
      <xsl:text>, </xsl:text>
    </xsl:if>
    <xsl:if test="position() = last()-1">
      <xsl:text> and </xsl:text>
    </xsl:if>
  </xsl:for-each>

在此输入上运行时:

<bankguarantees>
  <bankguaranteedata>
    <producttypes>
      <option id="A">selected</option>
      <option id="B"/>
      <option id="C"/>
      <option id="D"/>
      <option id="E"/>
      <option id="F"/>
      <option id="G"/>
      <option id="H"/>
    </producttypes>
    <otherprodtypebox>sprockets</otherprodtypebox>
  </bankguaranteedata>
  <bankguaranteedata>
    <producttypes>
      <option id="A">selected</option>
      <option id="B"/>
      <option id="C"/>
      <option id="D">selected</option>
      <option id="E"/>
      <option id="F"/>
      <option id="G"/>
      <option id="H">selected</option>
    </producttypes>
    <otherprodtypebox>widgets</otherprodtypebox>
  </bankguaranteedata>
  <bankguaranteedata>
    <producttypes>
      <option id="A">selected</option>
      <option id="B">selected</option>
      <option id="C"/>
      <option id="D">selected</option>
      <option id="E"/>
      <option id="F"/>
      <option id="G"/>
      <option id="H">selected</option>
    </producttypes>
    <otherprodtypebox>cogs</otherprodtypebox>
  </bankguaranteedata>

</bankguarantees>

产生此输出:

A, B, D, widgets and cogs

这篇关于xslt排序列表,如果倍数仅打印一次的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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