创建Greasemonkey脚本以在找到时删除某些HTML行 [英] Create Greasemonkey script to Remove certain HTML lines when found
本文介绍了创建Greasemonkey脚本以在找到时删除某些HTML行的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试制作可以删除html中某些行的油脂猴子脚本
I'm trying to make grease monkey script that could remove certain lines in html
例如这样
<ul class="actionList" id="actionList" style="height: 158px;">
<li class="actionListItem minion minion-0 first">
<div class="header">
<div class="verbs">
<a data-tipped="Look at the XXX" class="view verb tip-static" href="#"></a>
<a title="Attack XXX" href="#" class="verb attack attack-1 action-attack-minion-2442 default"></a></div>
<a data-tipped="minion" data-name="XXX" class="icon tip-static" href="#"></a>XXX</div></li>
<li class="actionListItem minion minion-0">
<div class="header">
<div class="verbs">
<a data-tipped="Look at XXX" class="view verb tip-static" href="#"></a>
<a title="Attack XXX" href="#" class="verb attack attack-2 action-attack-minion-2442 default"></a></div>
<a data-tipped="minion" data-name="XXX" class="icon tip-static" href="#"></a>XXX</div></li>
<li class="actionListItem Minion Minion-0 last">
<div class="header"><div class="verbs"><a data-tipped="Look at the XXX" class="view verb tip-static" href="#"></a><a title="Attack XXX" href="#" class="verb attack attack-3 action-attack-Minion-2442 default"></a></div><a data-tipped="Minion" data-name="XXX" class="icon tip-static" href="#"></a>XXX</div></li></ul>
我要删除
尝试了这样的东西
$('li:contains("actionListItem minion minion-0")').parent().remove();
$('li:contains("actionListItem minion minion-0")').parent().remove();
在编写脚本方面我仍然是新手,无法正常工作.帮助将不胜感激
I'm still new in scripting its not working. Help would be appreciated
推荐答案
尝试一下:
$( ".doc" ).remove()
,这里是您的确切示例的答案( http://pl. tinypic.com/view.php?pic=1yl65u&s=8 ):
and here's answer for your exact example ( http://pl.tinypic.com/view.php?pic=1yl65u&s=8 ):
$('#actionList').empty();
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