按两个属性对对象数组进行排序 [英] Sort array of objects by two properties
本文介绍了按两个属性对对象数组进行排序的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
在使用NSSortDescriptor
之前,这很容易被问到并回答.但是是否有使用Array.sort()
的Swift标准方式?
This has been asked and answered before using NSSortDescriptor
where it is quite easy. But is there a Swift-standard way using Array.sort()
?
struct Sortable {
let isPriority: Bool
let ordering: Int
}
通过一个属性对Sortables
数组进行排序很简单:
Sorting an array of Sortables
by one property is simple:
sort { $0.ordering < $1.ordering }
但是我想按isPriority
然后按ordering
进行排序-而且我无法理解一个简单的语句来实现这一目标.
But I want to sort by isPriority
then by ordering
- and I can't get my head around a simple statement to make that happen.
推荐答案
是的,使用Array.sort()
代码:
var sorted = array.sorted({ (s1, s2) -> Bool in
if s1.isPriority && !s2.isPriority {
return true //this will return true: s1 is priority, s2 is not
}
if !s1.isPriority && s2.isPriority {
return false //this will return false: s2 is priority, s1 is not
}
if s1.isPriority == s2.isPriority {
return s1.ordering < s2.ordering //if both save the same priority, then return depending on the ordering value
}
return false
})
排序后的数组:
true - 10
true - 10
true - 12
true - 12
true - 19
true - 29
false - 16
false - 17
false - 17
false - 17
false - 18
另一个更短的解决方案:
let sorted = array.sorted { t1, t2 in
if t1.isPriority == t2.isPriority {
return t1.ordering < t2.ordering
}
return t1.isPriority && !t2.isPriority
}
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