排序php数据var [英] Sorting php data var
问题描述
更新:好的，谢谢大家.但是，当我用$ i替换var时，出现以下错误:
UPDATE: Ok, thanks everyone. But, when I replace var with $ i now get these errors:
array_multisort()[function.array-multisort]:参数1应该是数组或排序标志
array_multisort()[function.array-multisort]: Argument #1 is expected to be an array or a sort flag
和
max()[function.max]:仅给出一个参数时，该参数必须为数组
max()[function.max]: When only one parameter is given, it must be an array
这应该很容易理解我的代码，但是有人可以告诉我为什么我在运行代码时收到此错误吗?
This should be pretty easy to follow looking at my code, but can anyone tell me why I am getting this error when I run my code?
解析错误:语法错误，意外的T_VAR
Parse error: syntax error, unexpected T_VAR
我想按玩家编号对数据进行排序，然后最高点行应显示为红色:
I want to sort the data by player number, and then the highest point row should be colored red:
file1.php
file1.php
<!doctype html public "-//W3C//DTD HTML 4.0 //EN">
<html>
<head>
<title>Fantasy Football</title>
</head>
<body>
<form action="roster.php" method="POST">
<table border="1">
<tr><td>Player Name</td><td><input type="text" name="name"</td></tr>
<tr><td>Position</td><td><input type="text" name="position"</td></tr>
<tr><td>Number</td><td><input type="text" name="number"</td></tr>
<tr><td>Team</td><td><input type="text" name="team"</td></tr>
<tr><td>Points per game</td><td><input type="text" name="points"</td></tr>
<tr><td colspan="2" align="center"><input type="submit"></td></tr>
</table>
</form>
</body>
</html>
roster.php
roster.php
<?php
for($i = 0; $i < sizeof($players); $i++) {
list($name[],$team[],$number[],$position[],$points[]) = explode('|', $players[$i]);
}
array_multisort($number, $position, $name, $team, $points, SORT_DESC);
var mostPoints = max($points);
for($i = 0; $i < sizeof($players); $i++) {
if($points[$i]==mostPoints){
echo '<tr style="background:#F44">';
}else{
echo '<tr>';
}
echo '<td>'.$name[$i].'</td><td>'.$team[$i].'</td><td>'.$number[$i].'</td>
<td>'.$position [$i].'</td><td>'.$points[$i].'</td></tr>';
}
?>
推荐答案
var mostPoints = max($points);
您最近是否经常使用JavaScript(或旧的PHP 4 OO)?
Have you been using JavaScript a lot lately (or old PHP 4 OO)?
PHP仅将var关键字用于旧的PHP4样式对象属性definitons.
PHP's only use of the var keyword was for old PHP4 style object property definitons.
拖放var部分.
此外，别忘了PHP变量sigil $.
Also, don't forget the PHP variable sigil $.
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