测试Quartz CronTrigger触发器 [英] Testing Quartz CronTrigger trigger

问题描述

假设我有一个与

<bean id="midMonthCronTrigger" class="org.springframework.scheduling.quartz.CronTriggerBean">
    <property name="jobDetail" ref="reminderJobDetail" />
    <property name="cronExpression" value="0 0 6 15W * ?" />
</bean>

类似的CronTriggerBean

<bean id="midMonthCronTrigger" class="org.springframework.scheduling.quartz.CronTriggerBean">
    <property name="jobDetail" ref="reminderJobDetail" />
    <property name="cronExpression" value="0 0 6 15W * ?" />
</bean>

测试此bean实际上将在其指定日期即在最接近每个月15日的凌晨6点触发的最佳方法是什么?

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更新:这应该是单元测试，所以我不会启动虚拟机或更改系统时间.

解决方案

首先，测试CronTriggerBean本身没有意义.它是spring框架的一部分，并且已经过测试.

更好的测试方法可能是测试您的cron表达式是否符合您的期望.这里的一种选择是使用Quartz的CronExpression类.给定一个CronExpression对象，您可以调用getNextValidTimeAfter(Date)，该表达式将在给定日期之后的下一次触发表达式时返回.

Assuming that I have a CronTriggerBean similar to

<bean id="midMonthCronTrigger" class="org.springframework.scheduling.quartz.CronTriggerBean">
    <property name="jobDetail" ref="reminderJobDetail" />
    <property name="cronExpression" value="0 0 6 15W * ?" />
</bean>

What is the best way to test that this bean will actually trigger at its specified date, i.e. on the weekday closest to the 15th of each month at 6 AM?

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Update: This is supposed to be an unit test, so I'm not going to fire up a VM or change the system time.

解决方案

Well firstly, there's no point in testing CronTriggerBean itself. It's part of the spring framework, and has already been tested.

A better test might be to test that your cron expression is what you expect. One option here is to use Quartz's CronExpression class. Given a CronExpression object, you can call getNextValidTimeAfter(Date), which returns the next time after the given Date when the expression will fire.

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