调用Spring RestController时，使用Spring的RestTemplate转义URL变量的正确方法是什么? [英] What's the proper way to escape URL variables with Spring's RestTemplate when calling a Spring RestController?

问题描述

调用RestTemplate.exchange进行获取请求时，例如:

When calling RestTemplate.exchange to do a get request, such as:

String foo = "fo+o";
String bar = "ba r";
restTemplate.exchange("http://example.com/?foo={foo}&bar={bar}", HttpMethod.GET, null, foo, bar)

正确地对get请求转义URL变量是什么?

what's the proper to have the URL variables correctly escaped for the get request?

具体地说，我如何正确地获得加号(+)，因为

Specifically, how do I get pluses (+) correctly escaped because Spring is interpreting as spaces, so, I need to encode them.

我尝试像这样使用UriComponentsBuilder:

String foo = "fo+o";
String bar = "ba r";
UriComponentsBuilder ucb = UriComponentsBuilder.fromUriString("http://example.com/?foo={foo}&bar={bar}");
System.out.println(ucb.build().expand(foo, bar).toUri());
System.out.println(ucb.build().expand(foo, bar).toString());
System.out.println(ucb.build().expand(foo, bar).toUriString());
System.out.println(ucb.build().expand(foo, bar).encode().toUri());
System.out.println(ucb.build().expand(foo, bar).encode().toString());
System.out.println(ucb.build().expand(foo, bar).encode().toUriString());
System.out.println(ucb.buildAndExpand(foo, bar).toUri());
System.out.println(ucb.buildAndExpand(foo, bar).toString());
System.out.println(ucb.buildAndExpand(foo, bar).toUriString());
System.out.println(ucb.buildAndExpand(foo, bar).encode().toUri());
System.out.println(ucb.buildAndExpand(foo, bar).encode().toString());
System.out.println(ucb.buildAndExpand(foo, bar).encode().toUriString());

并显示:

http://example.com/?foo=fo+o&bar=ba%20r
http://example.com/?foo=fo+o&bar=ba r
http://example.com/?foo=fo+o&bar=ba r
http://example.com/?foo=fo+o&bar=ba%20r
http://example.com/?foo=fo+o&bar=ba%20r
http://example.com/?foo=fo+o&bar=ba%20r
http://example.com/?foo=fo+o&bar=ba%20r
http://example.com/?foo=fo+o&bar=ba r
http://example.com/?foo=fo+o&bar=ba r
http://example.com/?foo=fo+o&bar=ba%20r
http://example.com/?foo=fo+o&bar=ba%20r
http://example.com/?foo=fo+o&bar=ba%20r

在某些情况下，空格可以正确地转义，但是加号永远不会转义.

The space is correctly escaped in some instances, but the plus is never escaped.

我也这样尝试过UriTemplate:

String foo = "fo+o";
String bar = "ba r";
UriTemplate uriTemplate = new UriTemplate("http://example.com/?foo={foo}&bar={bar}");
Map<String, String> vars = new HashMap<>();
vars.put("foo", foo);
vars.put("bar", bar);
URI uri = uriTemplate.expand(vars);
System.out.println(uri);

具有完全相同的结果:

http://example.com/?foo=fo+o&bar=ba%20r

推荐答案

显然，正确的方法是定义工厂并更改编码模式:

Apparently, the correct way of doing this is by defining a factory and changing the encoding mode:

String foo = "fo+o";
String bar = "ba r";
DefaultUriBuilderFactory factory = new DefaultUriBuilderFactory();
factory.setEncodingMode(DefaultUriBuilderFactory.EncodingMode.VALUES_ONLY);
URI uri = factory.uriString("http://example.com/?foo={foo}&bar={bar}").build(foo, bar);
System.out.println(uri);

打印出来:

http://example.com/?foo=fo%2Bo&bar=ba%20r

此处记录了以下内容: https://docs.spring.io/spring/docs/current/spring-framework-reference/web.html#web-uri-encoding

This is documented here: https://docs.spring.io/spring/docs/current/spring-framework-reference/web.html#web-uri-encoding

这篇关于调用Spring RestController时，使用Spring的RestTemplate转义URL变量的正确方法是什么?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！