如何避免使用while和find的subshel​​l行为? [英] How to avoid subshell behaviour using while and find?

问题描述

因为我自己陷入了困境，所以我提出了一个问题，并在此给出了答案.如果find遍历命令找到的内容，则在bash执行该命令.因此，您无法在结果中填充数组并在循环后使用它.

Because I trapped into this myself, I asked a question and did give also the answer here. If find iterates over what the command did find, this is executed from bash in a subshell. So you can not fill an array with results and use it after your loop.

推荐答案

您必须将语法从以下位置更改:

You have to change the syntax from:

i=0
find $cont_dirs_abs -type l -exec test -e {} \; -print0 | while IFS= read -r -d '' lxc_storage_abspath; do
    lxcname=${lxc_storage_abspath##*/}
    ...
    lxcnames[$i]="$lxcname"
    let "i+=1"
done

到

i=0
while IFS= read -r -d '' lxc_storage_abspath; do
    lxcname=${lxc_storage_abspath##*/}
    ...
    lxcnames[$i]="$lxcname"
    let "i+=1"
done < <(find $cont_dirs_abs -type l -exec test -e {} \; -print0)

就我而言，在此循环之后，我可以访问bash数组$lxcnames:

In my case i can after this loop access the bash array $lxcnames:

i=0
for lxcname in ${lxcnames[*]}; do
    ...
done

希望对任何人都有帮助.

Hope that helps anybody.

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