如何取消分配从Swift结构引用的UnsafeMutablePointer [英] How to dealloc UnsafeMutablePointer referenced from Swift struct

问题描述

如果我有这样的Swift结构:

If I have a Swift struct like this:

struct ViewBox {
    let pointer: UnsafeMutablePointer<UIView>
    init() {
        pointer = UnsafeMutablePointer<UIView>.alloc(1)
    }
}

当结构被释放时，我应该如何确保指针被正确地释放?我不能对Swift结构使用deinit或dealloc方法.

how should I ensure, that the pointer is properly deallocated, when the struct is deallocated? I can't use deinit or dealloc methods for Swift structs.

还是我不必在乎，它是自动发生的?

Or I don't have to care and it's happening automatically?

推荐答案

您可以将指针包装在一个类中.像这样:

You could wrap the pointer in a class. Something like this:

struct ViewBox {
    class WrappedPointer() {    
        let pointer: UnsafeMutablePointer<UIView>

        init() {
            pointer = UnsafeMutablePointer<UIView>.alloc(1)
        }

        deinit {
            pointer.dealloc(1)
        }
    }

    let wrappedPointer = WrappedPointer()
}

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