如何将文件夹中的所有.csv文件转换为具有多个工作表标签(每个.csv 1个)的单个.xlsx文件? [英] How can I convert all .csv files in a folder into a single .xlsx file with multiple worksheet tabs (1 for each .csv)?

问题描述

我有一个包含20个左右.csv文件的文件夹.我想用多个工作表标签(每个.csv 1个)创建一个.xlsx文件(excel文件).

I have a folder with 20 or so .csv files. I want to create a single .xlsx file (excel file) with multiple worksheet tabs (1 for each .csv).

有人可以推荐一个简单的脚本来执行此操作，而用户只需要指定两件事即可:带有.csv文件的文件夹&新的.xlsx文件的路径?

Can somebody recommend a simple script to do this where the user only needs to specify 2 things: the folder with the .csv files & the path to the new .xlsx file?

我在此线程中发现了相同的问题，但没有答案，我可以理解:

I found the same question at this thread but without an answer I could understand:

https://superuser.com/questions/742454/how-to-convert-many-csv-files-into-1-xlsx-file-with-multiple-tabs?rq=1

谢谢，

推荐答案

以下代码将文件夹名称(包含多个csv文件)作为输入，并创建输出为具有多个工作表的单个xls文件

The following code takes folder name (with multiple csv files) as input and creates output as a single xls file with multiple sheets

import xlwt, csv, os

csv_folder = "Output/"

book = xlwt.Workbook()
for fil in os.listdir(csv_folder):
    sheet = book.add_sheet(fil[:-4])
    with open(csv_folder + fil) as filname:
        reader = csv.reader(filname)
        i = 0
        for row in reader:
            for j, each in enumerate(row):
                sheet.write(i, j, each)
            i += 1

book.save("Output.xls")

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