别名模板参数包 [英] Aliasing a template parameter pack

问题描述

剧情

也许这个问题是重复的，但是我对模板编程还是比较陌生，实际上我找不到简单和简短解决方案(->仅找到兆字节的" roxxor-template-magic "(我不理解)匹配我的具体和简单问题，因此我现在有点迷失了.

Hi, maybe this question is a duplicate, but I am relative new to template programming and actually I am not able to find a simple and short solution (-> only finding megabytes of "roxxor-template-magic" which I don't understand) matching my concrete and simple problem and so I feel a little bit lost now.

预信息

我想使用"type_container"作为类的模板参数.容器是一个简单的结构，其中还应包含一些用于模板参数包的 typedefs .

I want to use a "type_container" as template parameter for a class. The container is a simple struct, which should also contain some typedefs for template parameter packs.

问题:(与底部的示例有关)

如何在容器结构中定义和命名类型列表，以及如何访问它们并将其转发到工厂类中所需的实体? (没有提升，只有C ++ 11/14/17 )

How can I define and alias the type-lists in the container-struct and how can I access and forward them to the needed entities in the factory-class? (No boost and only C++11/14/17)

示例:(如果需要，可以编译)

#include <map>
#include <vector>
#include <string>
#include <stack>

struct MY_TYPE_CONTAINER
{
    using TYPE_MAP            = std::map<int, int>;
    using TYPE_VECTOR         = std::vector<double>;
    using PARAMETER_PACK1 = //? -> ...T -> int, std::stack<int>, int
    using PARAMETER_PACK2 = //? -> ...T -> double, int, std::string
};

template <typename TYPES>
struct Factory
{
    typename TYPES::TYPE_MAP                       m_map;
    typename TYPES::TYPE_VECTOR                    m_vector;
    typename std::tuple<TYPES::PARAMETER_PACK1...> m_tuple;
    typename std::tuple<std::shared_ptr<TYPES::PARAMETER_PACK1>...> m_tuple2;
    void handlePack2(TYPES::PARAMETER_PACK2... args) { }
};


int main()
{
    Factory<MY_TYPE_CONTAINER> oStaticFactory;
    oStaticFactory.handlePack2(2.0, 1, "hi");
    return 0;
}

当前(最佳?)精心设计的解决方案(可编译)(基于John Zwinck的回答)

#include <map>
#include <vector>
#include <string>
#include <stack>
#include <memory>

struct MY_TYPE_CONTAINER
{
    using TYPE_MAP                    = std::map<int, int>;
    using TYPE_VECTOR                 = std::vector<double>;
    using PARAMETER_PACK1             = std::tuple<int, std::stack<int>, int>;
    using PARAMETER_SHARED_PTR_PACK_1 = std::tuple<std::shared_ptr<int>, std::shared_ptr<std::stack<int>>, std::shared_ptr<int>>;
    using PARAMETER_PACK2             = std::tuple<double, int, std::string>;
};

template <typename TYPES>
class Factory
{
    typename TYPES::TYPE_MAP                    m_map;
    typename TYPES::TYPE_VECTOR                 m_vector;
    typename TYPES::PARAMETER_PACK1             m_tuple;
    typename TYPES::PARAMETER_SHARED_PTR_PACK_1 m_tuple2;

    void handlePack2Impl(typename TYPES::PARAMETER_PACK2 tup) {};

public:
    template <typename... Args>
    void handlePack2(Args... args) { handlePack2Impl(std::make_tuple(args...)); }
};

int main()
{
    Factory<MY_TYPE_CONTAINER> oStaticFactory;
    oStaticFactory.handlePack2(2.0, 1, "hi");
    return 0;
}

推荐答案

您实际上可以使用tuple:

using PARAMETER_PACK1 = std::tuple<int, std::stack, int>;
using PARAMETER_PACK2 = std::tuple<double, int, std::string>;

typename TYPES::PARAMETER_PACK1 m_tuple;

然后您将遇到一个问题-如何声明这样的内容:

Then you're left with one problem--how to declare something like this:

void handlePack2(TYPES::PARAMETER_PACK2... args);

也许:

void handlePack2Impl(typename TYPES::PARAMETER_PACK2 tup);

template <typename... Args>
void handlePack2(Args... args) { handlePack2Impl(std::make_tuple(args...)); }

有关更多想法，请从此处开始:元组到参数包(但是请注意，这里有模板元编程！

For more ideas, start here: Tuple to parameter pack (but beware, there is template meta-programming!

这篇关于别名模板参数包的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！